Question

How do you solve $ \dfrac{x}{3}+5=10 $ ?

Answer 1

Hint: By solving this equation we have to find the value of the variable given in the equation i. e. $ x $ . To solve the equation we will use basic algebraic calculations like addition, subtraction, division, and multiplication. First, we will multiply by 3 on both sides of the equation then simplify the obtained equation to get the desired answer.

Complete step by step answer:
We have been given an equation $ \dfrac{x}{3}+5=10 $ .
We have to solve the given equation.
As the given equation is a linear equation in one variable i.e. we have to find the value of $ x $ by solving the equation.
Now, to solve the equation first we will multiply the given equation by 3 we get
\[\Rightarrow \dfrac{x}{3}\times 3+5\times 3=10\times 3\]
Now, solving further we get
\[\Rightarrow x+15=30\]
Now, shifting the constant terms on RHS we get
\[\Rightarrow x=30-15\]
Now, simplifying further we get
\[\Rightarrow x=15\]
So on solving the equation $ \dfrac{x}{3}+5=10 $ we get $ x=15 $ .
We can verify the solution of the equation by putting the obtained value in the equation and make the equation true.
For this question we get $ x=15 $
To verify the answer let us put the $ x=15 $ in the given equation $ \dfrac{x}{3}+5=10 $
Now, substituting the value in the LHS we get
 $ \begin{align}
  & \Rightarrow \dfrac{15}{3}+5 \\
 & \Rightarrow 5+5 \\
 & \Rightarrow 10 \\
\end{align} $ which is equal to RHS.
Hence $ x=15 $ is the correct answer.

Note:
Avoid calculation mistakes to solve this type of questions, also be careful while shifting the terms. Alternatively we can solve the given equation as :
 $ \dfrac{x}{3}+5=10 $
We will shift 5 to the RHS we get
 $ \begin{align}
  & \Rightarrow \dfrac{x}{3}=10-5 \\
 & \Rightarrow \dfrac{x}{3}=5 \\
\end{align} $
Now, cross multiplying we get
 $ \begin{align}
  & \Rightarrow x=5\times 3 \\
 & \Rightarrow x=15 \\
\end{align} $