Question

How do you solve $\dfrac{n}{3} - 5 = 12$?

Answer 1

Hint:In order to determine the value of variable$n$ in the above equation use the rules of transposing terms to transpose terms having $n$on the Left-hand side and constant value terms on the Right-Hand side of the equation. Solving like terms and multiplying both sides of the equation with the denominator of variable$n$will lead to your required result.

Complete step by step solution:
We are given a linear equation in one variable $\dfrac{n}{3} - 5 = 12$.and we have to solve this equation for variable ($x$).

$ \Rightarrow \dfrac{n}{3} - 5 = 12$

Now combining like terms on both of the sides. Terms having $n$will on the Left-Hand side of the equation and constant terms on the right-hand side .

Let’s recall one basic property of transposing terms that on transposing any term from one side to another the sign of that term gets reversed .In our case,$ - 5$in the left hand side will become $5$on the right hand side .

After transposing terms our equation becomes
$ \Rightarrow \dfrac{n}{3} = 12 + 5$

Now, solving the Right-hand side, the value of $n$is
$\dfrac{n}{3} = 17$

n = 51

Therefore, the solution to the equation $\dfrac{n}{3} - 5 = 12$is equal to $n = 51$.

Note:Linear Equation: A linear equation is an equation which can be represented in the form of $ax + c$where $x$is the unknown variable and a,c are the numbers known where $a \ne 0$.

If $a = 0$then the equation will become a constant value and will no longer be a linear equation .

The degree of the variable in the linear equation is of the order 1.