Question

How do you solve \[\dfrac{{|a - 5|}}{8}\, = 5\]?

Answer 1

Hint:Here the equation is an algebraic equation that is a combination of constant and variables. we have to solve the given equation for variable a. Since the equation involves the modulus, by using the definition of modulus or absolute value and simple arithmetic operation we determine the value of a.

Complete step by step explanation:
The absolute value or modulus of a real function f(x), it is denoted as |f(x)|, is the non-
negative value of f(x) without considering its sign. The value of |f(x)| defined as
\[|f(x)| = \left\{ \begin{array}{*{20}{c}}
{ + f(x)\,;}&{f(x) \geqslant 0}
\end{array} \\
\begin{array}{*{20}{c}}
{ - f(x)\,;}&{f(x) < 0}
\end{array} \\
\right\}\]
Now consider the given question \[\dfrac{{|a - 5|\,}}{8} = 5\]
Multiply the above inequality with 8 we have
\[|a - 5| = 40\]
By the definition of absolute number, we are determined the unknown variable and
By definition the modulus, separate \[|a - 5|\, = 40\] into two equations:
\[a - 5 = 40\] (1)
and
\[ - \left( {a - 5} \right) = 40\] (2)
Consider the equation (1)
\[ \Rightarrow \,\,\,a - 5 = 40\]
Add both side by 5, then
\[ \Rightarrow \,\,\,a - 5 + 5 = 40 + 5\]
On simplification, we get
\[\therefore \,\,\,a = 45\]
Now consider the equation (2)
\[ \Rightarrow \,\,\, - \left( {a - 5} \right) = 40\]
First multiply the -ve sign inside to the parenthesis on LHS.
\[ \Rightarrow \,\,\, - a + 5 = 40\]
Add -5 on both side, then
\[ \Rightarrow \,\,\, - a + 5 - 5 = 40 - 5\]
On simplification, we get
\[ \Rightarrow \,\,\, - a = 35\]
Multiply or Cancel – ve sign on both side
\[\therefore \,\,\,a = - 35\]
Hence, the value of x in the equation \[\dfrac{{|a - 5|}}{8}\, = 5\] is 45 and -35.
Verification:
Put x=45 to the equation \[\dfrac{{|a - 5|\,}}{8}\], then
\[ \Rightarrow \,\,\,\dfrac{{|45 - 5|\,}}{8}\]
\[ \Rightarrow \,\,\,\dfrac{{|40|\,}}{8}\]
\[ \Rightarrow \,\,\,\dfrac{{40}}{8} = 5\]
\[\therefore \,\,\dfrac{{\,|a - 5|\,}}{8} = 5\]
And
Put x=-35 to the equation \[\dfrac{{|a - 5|}}{8}\], then
\[ \Rightarrow \,\,\,\dfrac{{| - 35 - 5|\,}}{8}\]
\[ \Rightarrow \,\,\,\dfrac{{| - 40|\,}}{8}\]
By the definition of modulus \[| - x|\, = x\], then
\[ \Rightarrow \,\,\,\dfrac{{40}}{8} = 5\]
\[\therefore \,\,\dfrac{{\,|a - 5|\,}}{8} = 5\]
Hence verified.

Note: The algebraic equation or an expression is a combination of variables and constants, it also contains the coefficient. The alphabets are known as variables. The x, y, z etc., are called as variables. The numerals are known as constants. The numeral of a variable is known as co-efficient. we must know about the modulus definition.