Question

How do you solve $\dfrac{5}{6} = \dfrac{b}{{48}}$?

Answer 1

Hint: This problem deals with solving with the value of the above equation which is a linear equation in one variable. Here in order to find the solution of the given above equation, the method of cross multiplication is applied to the above equation. Then transferring the like terms and the unlike terms together and then simplifying it further to get the desired result.

Complete step by step solution:
Given an equation which is a linear equation in one variable. Here this equation is varying in one variable which is equal to $b$.
The given equation is varying in the variable $b$.
Now consider the given by the equation which is given by $\dfrac{5}{6} = \dfrac{b}{{48}}$, as shown below:
$ \Rightarrow \dfrac{5}{6} = \dfrac{b}{{48}}$
Now applying the cross multiplication principle to the above equation as shown below:
$ \Rightarrow 5\left( {48} \right) = 6b$
Now dividing the above equation by 6 as shown below:
$ \Rightarrow 5\left( 8 \right) = b$
Simplifying the above equation that is simplifying the product on the left hand side of the above equation as shown below:
$\therefore b = 40$

The solution of the given equation $\dfrac{5}{6} = \dfrac{b}{{48}}$, here the value of b is 40.

Note: Please note that the above equation is solved by the process of cross multiplication. After applying the process of cross multiplication, grouping the like terms and the unlike terms together from one side and another side. The solution of this equation can also be done by multiplying the above equation with a common factor which the both of the denominators on both the sides of the equation, still ending up with the same answer.