Question

How do you solve $\dfrac{2}{3} - \dfrac{1}{6}$ ?

Answer 1

Hint: To solve this type of questions, first we will take the lowest common factors of the denominator of the given fraction and then apply the simple multiplication, addition, and subtraction operations to find the solution to the given fraction.

Complete step by step solution:.
As we know that when one number is divided into two parts, then one of the parts can be represented by the fraction. Mathematically notation of a fraction number can be denoted as $\dfrac{a}{b}$. Here, b cannot be equal to zero because when b tends to 0, then the fraction goes to infinity. Thus, the numbers a and b must be integers.
LCM is a mathematical operation. LCM is the common smallest number that is a multiple of two or more numbers. Suppose $a$ and $b$ are two numbers and $c$ is the LCM of the given number. That means $c$ is the smallest common multiple of the given numbers.
The addition, subtraction, multiplication, and division of two or more numbers are known as algebraic operations.
We will consider the given fraction expression.
$ \Rightarrow \dfrac{2}{3} - \dfrac{1}{6}$
Take the lowest common multiple (L.C.M) of the denominators of the above expression.
Since the denominators are 3 and 6. So, the L.C.M is 6.
Now we will solve the given expression.
$ \Rightarrow \dfrac{2}{3} - \dfrac{1}{6} = \dfrac{{4 - 1}}{6}$
After simplification we will get,
$ \Rightarrow \dfrac{2}{3} - \dfrac{1}{6} = \dfrac{3}{6}$
Now, we will write it in the simplest form as,
$\therefore \dfrac{2}{3} - \dfrac{1}{6} = \dfrac{1}{2}$

Therefore, the solution of the given fraction expression is $\dfrac{1}{2}$.

Note: Make sure we have to take the LCM of the denominators of the given expression. Do not take the HCF of the denominators. The algebraic operations (subtraction, addition, and multiplication) should be performed correctly.