Question

How do you solve 8x – 1 = 63?

Answer 1

Hint: Here in this problem, we are given a linear equation in one variable. We need to find the variable ‘x’ in this particular equation. We will keep ‘x’ alone on one side of the equation to solve the like terms. We know that like terms are those which either have the same variables or they are constants. And the given equation is the simplest linear equation because it contains only a single variable.

Complete step-by-step solution:
Now, let’s discuss the entire problem.
We already know that a linear equation is that equation in which the highest power of the variable is one. For example: In 5y + 9, ‘y’ has the power as one. And it also forms a straight line.
When we say linear equations in one variable, it means it contains only a single variable whose value needs to be found out. Here also, we have to find the value of ‘x’.
First write the equation given in question.
$\Rightarrow $8x – 1 = 63
Now take constant term i.e. 1 on the right side of the equation:
$\Rightarrow $8x = 63 + 1
$\Rightarrow $8x = 64
As we can see that 8 is in product form with the variable ‘x’, so it will be taken as denominator on the other side:
$\Rightarrow x=\dfrac{64}{8}$
Reduce the fraction:
$\therefore x=8$
This is the answer.

Note: If you feel that your obtained value is incorrect, you can easily check and verify the answer by placing it in the given equation. Let’s check and verify the solution.
$\Rightarrow $8x – 1 = 63
Place x = 8 in above equation, we get:
$\Rightarrow $8(8) – 1 = 63
Solve the left hand side:
$\Rightarrow $64 – 1 = 63
$\Rightarrow $63 = 63
That means the value we obtained is correct.