Question

How do you solve $6x-15=65+x$ ?

Answer 1

Hint: The equation given in the question is a linear equation in one variable so we can solve it by bringing all the x t sides and all constant to the other side. Then we will divide Both LHS and RHS by the coefficient of x to find the value of x.

Complete step-by-step answer:
The given equation is $6x-15=65+x$ which is a linear equation in one variable
So let’s bring all the x to LHS and all constant to RHS , we can see x is present in RHS
So subtracting x from LHS and RHS we get
5x – 15=65
Adding 15 both sides we get
$\Rightarrow 5x=80$
The coefficient of x is 5, so dividing both LHS and RHS by 5 we get
$\Rightarrow x=16$
So 16 is the solution of $6x-15=65+x$

Note: We can check whether our answer is correct or not putting the answer in the equation, so putting 16 in the equation $6x-15=65+x$ we get 96 - 15 = 65 + 16 which is correct so 16 is the correct answer. We can solve the equation by graphical method, to solve $2x+5=3x-7$ we can draw the graph of y = 6x - 15 and y = 65 + x, the intersection point is the solution of the equation.
We know that both the equations will form a straight line so maximum 1 solution will exist for the equation. The equation will have no solution if both the lines will be parallel and different.