Question

How do you solve $6x - 4 = 2x + 10$?

Answer 1

Hint: In order to determine the value of variable $ x $ in the above equation. Combining like terms by Using the rules of transposing terms to transpose terms having $ x $ on the left-hand side and constant value terms on the right-Hand side of the equation. Combine and solve like terms and divide the equation with coefficient of $ x $ to get your desired solution.

Complete step by step solution:
 We are given a linear equation in one variable $6x - 4 = 3x + 2$.and we have to solve this equation for variable ($x$).
$6x - 4 = 2x + 10$
Now combining like terms on both of the sides. Terms having $x$will on the left-Hand side of the equation and constant terms on the right-hand side.
Let’s recall one basic property of transposing terms that on transposing any term from one side to another the sign of that term gets reversed .
After transposing terms our equation becomes
$6x - 2x = 10 + 4$
Solving all the like term by resolving the operators,
$4x = 14$
Dividing both sides of the equation with the coefficient of $x$i.e. $3$, we obtain the value of $x$as
$
  \dfrac{{4x}}{4} = \dfrac{14}{4} \\
  x =\dfrac{14}{4} \;
 $
Therefore, the solution to the given equation is equal to$ x =\dfrac{14}{4} $..
So, the correct answer is “ $ x =\dfrac{14}{4} $ .”.

Note: Linear Equation in one variable: A linear equation is a equation which can be represented in the form of $ ax + c $ where $ x $ is the unknown variable and a,c are the numbers known where $ a \ne 0 $ .If $ a = 0 $ then the equation will become constant value and will no more be a linear equation .
The degree of the variable in the linear equation is of the order 1.
Every Linear equation has 1 root.