Question

How do you solve $ 6n = 4n + 3 $ ?

Answer 1

Hint: In order to determine the value of variable $ n $ in the above equation use the rules of transposing terms to transpose terms having $ n $ on the Left-hand side and constant value terms on the Right-Hand side of the equation. Solving like terms and solving for $ n $ you’ll get your required result.

Complete step-by-step answer:
We are given a linear equation in one variable $ 6n = 4n + 3 $ .and we have to solve this equation for variable ( $ n $ ).
 $ \Rightarrow 6n = 4n + 3 $
Now combining like terms on both of the sides. Terms having $ n $ will on the Left-Hand side of the equation and constant terms on the right-hand side.
Let’s recall one basic property of transposing terms that on transposing any term from one side to another the sign of that term gets reversed. In our case, $ 4n $ in the Right-hand side will become $ - 4n $ on the Left-hand side.
After transposing terms our equation becomes
 $ \Rightarrow 6n - 4n = 3 $
Now, solving the Left-hand side, we get
 $ \Rightarrow 2n = 3 $
Now dividing both sides of the with coefficient of variable $ n $ i.e. $ 2 $
 $
   \Rightarrow \dfrac{{2n}}{2} = \dfrac{3}{2} \\
   \Rightarrow n = \dfrac{3}{2} \;
  $
Therefore, the solution to the equation $ 6n = 4n + 3 $ is equal to $ n = \dfrac{3}{2} $ .
So, the correct answer is “ $ n = \dfrac{3}{2} $ ”.

Note: Linear Equation: A linear equation is a equation which can be represented in the form of $ ax + c $ where $ x $ is the unknown variable and a,c are the numbers known where $ a \ne 0 $ .If $ a = 0 $ then the equation will become constant value and will no more be a linear equation .
The degree of the variable in the linear equation is of the order 1.
Every Linear equation has 1 root.