Question

How do you solve $ 6a + 5a = - 11 $ ?

Answer 1

Hint: In order to determine the value of variable $ x $ in the above equation use the basic rule of combining the like terms having variable( \[a\] ) on the left hand side by simply adding up the coefficients and later divide both sides of the equation with the coefficient of the variable( \[a\] ),you’ll obtain your required answer.

Complete step-by-step answer:
We are given a linear equation in one variable $ 6a + 5a = - 11 $ .and we have to solve this equation for variable ( $ a $ ).
 $ \Rightarrow 6a + 5a = - 11 $
Now combining like terms on both of the sides. Terms having $ a $ will on the Left-Hand side of the equation and constant terms on the right-hand side .
On the left hand side of the we have sum of like terms having variable( $ a $ ),so we will take variable( $ a $ ) as common as add the constants as
 $
   \Rightarrow a\left( {6 + 5} \right) = - 11 \\
   \Rightarrow a\left( {11} \right) = - 11 \\
   \Rightarrow 11a = - 11 \;
  $
Now dividing both sides of the equation with the coefficient of variable ( $ a $ ) i.e. $ 11 $ .
 \[
   \Rightarrow \dfrac{{11a}}{{11}} = \dfrac{{ - 11}}{{11}} \\
   \Rightarrow a = - 1 \;
 \]
Therefore, the solution to the equation $ 6a + 5a = - 11 $ is equal to \[a = - 1\]
So, the correct answer is “a = - 1”.

Note: Linear Equation: A linear equation is a equation which can be represented in the form of $ ax + c $ where $ x $ is the unknown variable and a,c are the numbers known where $ a \ne 0 $ .If $ a = 0 $ then the equation will become constant value and will no more be a linear equation .
The degree of the variable in the linear equation is of the order 1.
Every Linear equation has 1 root.
Basic property of transposing terms states that on transposing any term from one side to another the sign of that term gets reversed .