How do you solve \[6=1-2n+5\]?
Answer
584.4k+ views
Hint: Rearrange the terms of the given equation by taking the terms containing the variable ‘n’ to the L.H.S. and take the constant terms to the R.H.S. Now, apply the simple arithmetic operations like: - addition, subtraction, multiplication and division, whichever needed, to simplify the equation. Find the value of ‘n’ to get the answer.
Complete answer:
We have been provided with the equation: \[6=1-2n+5\] and we are asked to solve this equation. That means we have to find the value of n.
As we can see that the given equation is a linear equation in one variable which is ‘n’, so now taking the terms containing the variable ‘n’ to the left-hand side (L.H.S.) and the constant terms to the right-hand side (R.H.S.), we get,
\[\begin{align}
& \Rightarrow 2n=1+5-6 \\
& \Rightarrow 2n=6-6 \\
& \Rightarrow 2n=0 \\
\end{align}\]
Dividing both the sides with 2 and using the fact that ‘0 divided by any non – zero number equals 0’, we get,
\[\Rightarrow \dfrac{2n}{2}=\dfrac{0}{2}\]
On simplifying we get,
\[\Rightarrow n=0\]
Hence, the value of n is 0.
Note: One may note that we have been provided with a single equation only. The reason is that we have to find the value of only one variable, that is ‘n’. So, in general if we have to solve an equation having ‘m’ number of variables then we should be provided with ‘m’ number of equations. Now, one can check the answer by substituting the obtained value of ‘n’ in the equation provided in the question. We have to determine the value of L.H.S. and R.H.S. separately and if they are equal then our answer is correct.
Complete answer:
We have been provided with the equation: \[6=1-2n+5\] and we are asked to solve this equation. That means we have to find the value of n.
As we can see that the given equation is a linear equation in one variable which is ‘n’, so now taking the terms containing the variable ‘n’ to the left-hand side (L.H.S.) and the constant terms to the right-hand side (R.H.S.), we get,
\[\begin{align}
& \Rightarrow 2n=1+5-6 \\
& \Rightarrow 2n=6-6 \\
& \Rightarrow 2n=0 \\
\end{align}\]
Dividing both the sides with 2 and using the fact that ‘0 divided by any non – zero number equals 0’, we get,
\[\Rightarrow \dfrac{2n}{2}=\dfrac{0}{2}\]
On simplifying we get,
\[\Rightarrow n=0\]
Hence, the value of n is 0.
Note: One may note that we have been provided with a single equation only. The reason is that we have to find the value of only one variable, that is ‘n’. So, in general if we have to solve an equation having ‘m’ number of variables then we should be provided with ‘m’ number of equations. Now, one can check the answer by substituting the obtained value of ‘n’ in the equation provided in the question. We have to determine the value of L.H.S. and R.H.S. separately and if they are equal then our answer is correct.
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