Question

How do you solve $6 \div 3(2 + 1)$ ?

Answer 1

Hint: To solve this question we should know about how given numerical operation operates in fixed sequence. To solve this we follow a simple method:
Bodmas rule:
B O D M A S
That means first we solve brackets , then orders, then division, then multiplication, then addition, then at last we do subtraction operation.

Complete step by step solution:
As given in question $6 \div 3(2 + 1)$ .
To solve this question we should follow BODMAS rule:
So we will go step by step:
Step 1: first solve operator inside the bracket:
$\Rightarrow 6 \div 3(2 + 1) = 6 \div 3.3$
Step 2: then solve orders in the numerical operation:
$\Rightarrow 6 \div 3.3 = 6 \div 9$
Step 3: Then solve division in the numerical operator:
$\Rightarrow 6 \div 9 = \dfrac{6}{9}$

Hence, $6 \div 3(2 + 1) = \dfrac{6}{9}$

Note: BODMAS is an acronym and it stands for bracket, order, division, multiplication, Addition, and subtraction. In certain regions, PEMDAS (parentheses, exponents, multiplication, division, addition, and subtraction) is used, which is the synonym of BODMAS. The mistake which you can do is in the second step where instead of solving the order you can do division first. So, your answer is wrong. In using the BODMAS rule we should keep in mind about the sequence on which operation carried on.