Question

How do you solve $5\left( 2x-3 \right)=15$ ?

Answer 1

Hint: This is a linear equation in one variable, so one equation is enough to find the value of the unknown. We can separate the entire x and all constants. We can bring all the x to LHS and constant to LHS and then solve for x by dividing both LHS and RHS by coefficient of x.

Complete step by step answer:
The given equation in the question is $5\left( 2x-3 \right)=15$
Further solving by multiplying 5 with the term 2x - 3 in LHS and Keeping the RHS unchanged, we get
$\Rightarrow 10x-15=15$
Now we can bring all the x to LHS and all the constant to RHS
Now adding 15 in LHS and RHS so that the term -15 can cancel out from LHS
$\Rightarrow 10x=30$
Now we can divide LHS and RHS by 10 so that the coefficient of x will become 1 in LHS
$\Rightarrow x=3$

We can see the value of x is 3.

Note: We only need one equation to solve the system of equations having one unknown variable. If a system contains n unknown variables then we need at least n equations to find the value of all the variables. Sometimes n equations are enough if the delta value of the entire coefficients is 0. If a system contains n unknown variables and less than n equations then the number of solutions tends to infinity and on the other hand if the system contains more than n equations then there may not exist any solution to the system of equations.