Question

How do you solve \[5\left( 2x-3 \right)+8=9\]?

Answer 1

Hint: We will use a linear equation concept to solve this problem. First we have to remove the parenthesis and then we have to combine like terms. We have to make x containing terms on one side and remaining on the other side. Then by doing some arithmetic operations we will get the answer.

Complete step by step answer:
Given equation is
\[5\left( 2x-3 \right)+8=9\]
First we have to remove the parentheses. For doing this we have to multiply the terms inside the parenthesis with 5 . we will get
\[\Rightarrow 10x-15+8=9\]
By simplifying we will get
\[\Rightarrow 10x-7=9\]
Now we have to combine like terms on one side. So we have to keep x containing terms one side and constants on the other side.
To make x containing terms on one side we have to add 7 on both sides of the equation.
By adding 7 we will get
\[\Rightarrow 10x-7+7=9+7\]
By simplifying it we will get
\[\Rightarrow 10x=16\]
Now we have to find the x value by simplifying the equation.
To get the value of x we have to divide with 10 on both sides of the equation.
After dividing with 10 we will get
\[\Rightarrow \dfrac{10x}{10}=\dfrac{16}{10}\]
By simplifying it we will get
\[\Rightarrow x=\dfrac{8}{5}\]
We can leave this and can also convert into decimal form
By converting into decimal form we will get
\[\Rightarrow x=1.6\]
So by solving the equation we get the x value as \[1.6\].

Note:
We can also do it in other ways. We can do it by first taking 8 from LHS to RHS then dividing both sides with 5 and then solving for x. But the above method is easier to implement and remember.