Answer
385.5k+ views
Hint: In this problem, we have to solve the given equation and find the value of x. We can first subtract the number 7 on both the left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side. We can then divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
Complete step by step answer:
We know that the given equation to be solved to find the value of x is,
\[4x+7=27\]
We can first subtract the number 7 on both left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side, we get
\[\begin{align}
& \Rightarrow 4x+7-7=27-7 \\
& \Rightarrow 4x=20 \\
\end{align}\]
We can now divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
\[\Rightarrow \dfrac{4x}{4}=\dfrac{20}{4}\]
We can now cancel the similar terms on the left-hand side and use multiplication tables to can the terms on the right-hand side, we get
\[\Rightarrow x=5\]
Therefore, the value of x = 5.
Note: We can also check this value by substituting the resulted value in the given equation, we get
\[\begin{align}
& \Rightarrow 4\left( 5 \right)+7=27 \\
& \Rightarrow 20+7=27 \\
\end{align}\]
We can see that we got the same number on both the left-hand side and the right-hand side. Therefore, it is a correct value. Students make mistakes while using multiplication to simplify, we should know multiplication tables to solve these types of problems.
Complete step by step answer:
We know that the given equation to be solved to find the value of x is,
\[4x+7=27\]
We can first subtract the number 7 on both left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side, we get
\[\begin{align}
& \Rightarrow 4x+7-7=27-7 \\
& \Rightarrow 4x=20 \\
\end{align}\]
We can now divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
\[\Rightarrow \dfrac{4x}{4}=\dfrac{20}{4}\]
We can now cancel the similar terms on the left-hand side and use multiplication tables to can the terms on the right-hand side, we get
\[\Rightarrow x=5\]
Therefore, the value of x = 5.
Note: We can also check this value by substituting the resulted value in the given equation, we get
\[\begin{align}
& \Rightarrow 4\left( 5 \right)+7=27 \\
& \Rightarrow 20+7=27 \\
\end{align}\]
We can see that we got the same number on both the left-hand side and the right-hand side. Therefore, it is a correct value. Students make mistakes while using multiplication to simplify, we should know multiplication tables to solve these types of problems.
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