
How do you solve $4{e^{7x}} = 10273$?
Answer
532.2k+ views
Hint: First we have to divide each term of the given equation by $4$ and simplify. For this, divide each term in $4{e^{7x}} = 10273$ by $4$. Next, take the natural logarithm of both sides of the equation to remove the variable from the exponent. Next, expand the left side. For this, expand $\ln \left( {{e^{7x}}} \right)$ by moving $7x$ outside the logarithm. Next, divide each term by $7$ and simplify.
For this, divide each term in $7x = \ln \left( {\dfrac{{10273}}{4}} \right)$ by $7$. Then, we will get the solution of the given equation.
Formula used:
$\ln \left( {{a^m}} \right) = m\ln \left( a \right)$
$\ln \left( e \right) = 1$
Complete step by step solution:
Given equation: $4{e^{7x}} = 10273$
We have to find all possible values of $x$ satisfying a given equation.
So, first we have to divide each term by $4$ and simplify.
For this, divide each term in $4{e^{7x}} = 10273$ by $4$.
$ \Rightarrow \dfrac{{4{e^{7x}}}}{4} = \dfrac{{10273}}{4}$
Now, cancel the common factor of $4$.
$ \Rightarrow {e^{7x}} = \dfrac{{10273}}{4}$
Next, take the natural logarithm of both sides of the equation to remove the variable from the exponent.
$\ln \left( {{e^{7x}}} \right) = \ln \left( {\dfrac{{10273}}{4}} \right)$
Now, expand the left side.
For this, expand $\ln \left( {{e^{7x}}} \right)$ by moving $7x$ outside the logarithm as $\ln \left( {{a^m}} \right) = m\ln \left( a \right)$.
$ \Rightarrow 7x\ln \left( e \right) = \ln \left( {\dfrac{{10273}}{4}} \right)$
We know that the natural logarithm of $e$ is $1$.
$ \Rightarrow 7x \times 1 = \ln \left( {\dfrac{{10273}}{4}} \right)$
Multiply $7x$ by $1$, we get
$ \Rightarrow 7x = \ln \left( {\dfrac{{10273}}{4}} \right)$
Now, divide each term by $7$ and simplify.
For this, divide each term in $7x = \ln \left( {\dfrac{{10273}}{4}} \right)$ by $7$.
$ \Rightarrow \dfrac{{7x}}{7} = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$
Cancel the common factor of $7$.
$ \Rightarrow x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$
The result can be shown in multiple forms.
Exact Form: $x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$
Decimal Form: $x = 1.121568573$
Final solution: Hence, $x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$ or $x = 1.121568573$ is the solution of $4{e^{7x}} = 10273$.
Note: In above question, we can find the solutions of given equation by plotting the equation, $4{e^{7x}} = 10273$ on graph paper and determine all its solutions.
From the graph paper, we can see that $x = 1.121568573$ is the solution of $4{e^{7x}} = 10273$.
Final solution: Hence, $x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$ or $x = 1.121568573$ is the solution of $4{e^{7x}} = 10273$.
For this, divide each term in $7x = \ln \left( {\dfrac{{10273}}{4}} \right)$ by $7$. Then, we will get the solution of the given equation.
Formula used:
$\ln \left( {{a^m}} \right) = m\ln \left( a \right)$
$\ln \left( e \right) = 1$
Complete step by step solution:
Given equation: $4{e^{7x}} = 10273$
We have to find all possible values of $x$ satisfying a given equation.
So, first we have to divide each term by $4$ and simplify.
For this, divide each term in $4{e^{7x}} = 10273$ by $4$.
$ \Rightarrow \dfrac{{4{e^{7x}}}}{4} = \dfrac{{10273}}{4}$
Now, cancel the common factor of $4$.
$ \Rightarrow {e^{7x}} = \dfrac{{10273}}{4}$
Next, take the natural logarithm of both sides of the equation to remove the variable from the exponent.
$\ln \left( {{e^{7x}}} \right) = \ln \left( {\dfrac{{10273}}{4}} \right)$
Now, expand the left side.
For this, expand $\ln \left( {{e^{7x}}} \right)$ by moving $7x$ outside the logarithm as $\ln \left( {{a^m}} \right) = m\ln \left( a \right)$.
$ \Rightarrow 7x\ln \left( e \right) = \ln \left( {\dfrac{{10273}}{4}} \right)$
We know that the natural logarithm of $e$ is $1$.
$ \Rightarrow 7x \times 1 = \ln \left( {\dfrac{{10273}}{4}} \right)$
Multiply $7x$ by $1$, we get
$ \Rightarrow 7x = \ln \left( {\dfrac{{10273}}{4}} \right)$
Now, divide each term by $7$ and simplify.
For this, divide each term in $7x = \ln \left( {\dfrac{{10273}}{4}} \right)$ by $7$.
$ \Rightarrow \dfrac{{7x}}{7} = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$
Cancel the common factor of $7$.
$ \Rightarrow x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$
The result can be shown in multiple forms.
Exact Form: $x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$
Decimal Form: $x = 1.121568573$
Final solution: Hence, $x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$ or $x = 1.121568573$ is the solution of $4{e^{7x}} = 10273$.
Note: In above question, we can find the solutions of given equation by plotting the equation, $4{e^{7x}} = 10273$ on graph paper and determine all its solutions.
From the graph paper, we can see that $x = 1.121568573$ is the solution of $4{e^{7x}} = 10273$.
Final solution: Hence, $x = \dfrac{{\ln \left( {\dfrac{{10273}}{4}} \right)}}{7}$ or $x = 1.121568573$ is the solution of $4{e^{7x}} = 10273$.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

