
How do you solve \[3x = 18\]?
Answer
544.5k+ views
Hint:
In the given question, we have been given an algebraic expression. In the expression, a constant is multiplied with a variable. The product of two is equal to another constant. We have to solve the expression. To do that, we first take the constant being multiplied with the variable to the other side. We do that by dividing this constant and the constant on the other side. That gives us the answer.
Formula Used:
If \[a \times b = c\], then \[b = \dfrac{c}{a}\]
Complete step by step solution:
The given expression to be simplified is:
\[3x = 18\]
We know, \[a \times b = c \Rightarrow b = \dfrac{c}{a}\].
Substituting \[a = 3\], \[b = x\] and \[c = 18\], we have,
\[x = \dfrac{{18}}{3} = 6\]
Note:
In the given question, we had to simplify the value of an expression. To do that, we take the term being multiplied with the constant to the other side. Then we apply the required operation, one which is opposite of what was being applied to the constant on the original side. Then we solve the other side and find the answer.
In the given question, we have been given an algebraic expression. In the expression, a constant is multiplied with a variable. The product of two is equal to another constant. We have to solve the expression. To do that, we first take the constant being multiplied with the variable to the other side. We do that by dividing this constant and the constant on the other side. That gives us the answer.
Formula Used:
If \[a \times b = c\], then \[b = \dfrac{c}{a}\]
Complete step by step solution:
The given expression to be simplified is:
\[3x = 18\]
We know, \[a \times b = c \Rightarrow b = \dfrac{c}{a}\].
Substituting \[a = 3\], \[b = x\] and \[c = 18\], we have,
\[x = \dfrac{{18}}{3} = 6\]
Note:
In the given question, we had to simplify the value of an expression. To do that, we take the term being multiplied with the constant to the other side. Then we apply the required operation, one which is opposite of what was being applied to the constant on the original side. Then we solve the other side and find the answer.
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