
How do you solve $3x + 4 = 5x - 10$ ?
Answer
550.5k+ views
Hint: One must remember in algebra, only the terms having the same degree of power of the variable can be added or subtracted. Here, we shift all the terms with the same power on the same side of the equation, and then performing the necessary operations, the value of $x$ can be found.
Complete step by step solution:
As we know in algebra, only the terms having the same power on the variable can be added or subtracted.
Here, the terms $5x\;$ and $3x\;$ have the same power of $x$ , and hence they can be added or subtracted from each other.
Similarly, the terms $4$ and $ - 10$ have the same power of $x$ , which is $0$ because any number with a power of $0$ is equal to $1$ .
Hence, these terms can also be written as $4{x^0}$ and $ - 10{x^0}$ . As they have the same power, these terms can be added or subtracted from each other.
To simplify the equation, let’s start by shifting the same power terms on the same side of the equation
The equation we are given here is
$3x + 4 = 5x - 10$
Now, adding $10\;$ on both the sides of the equation
$ \Rightarrow 3x + 4 + 10 = 5x - 10 + 10$
$ \Rightarrow 3x + 14 = 5x$
Now, subtracting $3x\;$ from both sides of the equation
$ \Rightarrow 3x - 3x + 14 = 5x - 3x$
$ \Rightarrow 14 = 5x - 3x$
Now, to explain the subtraction, let’s expand the terms $5x\;$ and $3x\;$ .
We know that $5x\;$ means $5$ times $x$ . Hence, expanding $5x\;$ as shown
$ \Rightarrow 5x = x + x + x + x + x$
Similarly, for $3x\;$ we can write
$ \Rightarrow 3x = x + x + x$
On subtracting them both we get,
$ \Rightarrow 14 = 2x$
Dividing both the sides by $2$ ,
$ \Rightarrow \dfrac{{14}}{2} = \dfrac{{2x}}{2}$
Factoring the numerator,
$ \Rightarrow \dfrac{{2 \times 7}}{2} = \dfrac{{2x}}{2}$
$ \Rightarrow x = 7$
Hence the solution for the given equation is $x = 7$.
Note: Another method for subtracting the terms with $x$ is by taking the common factor i.e. variable $x$ common and subtracting the numbers in the bracket. If one wants to check the accuracy of the solution, one can substitute the obtained value in the given equation and check if it satisfies the equation.
Putting $x = 7$ in the equation.
$ \Rightarrow 3x + 4 = 5x - 10$
$ \Rightarrow 3(7) + 4 = 5(7) - 10$
Now evaluate.
$ \Rightarrow 21 + 4 = 35 - 10$
$ \Rightarrow 25 = 25$
Since LHS=RHS, our answer is hence correct.
Complete step by step solution:
As we know in algebra, only the terms having the same power on the variable can be added or subtracted.
Here, the terms $5x\;$ and $3x\;$ have the same power of $x$ , and hence they can be added or subtracted from each other.
Similarly, the terms $4$ and $ - 10$ have the same power of $x$ , which is $0$ because any number with a power of $0$ is equal to $1$ .
Hence, these terms can also be written as $4{x^0}$ and $ - 10{x^0}$ . As they have the same power, these terms can be added or subtracted from each other.
To simplify the equation, let’s start by shifting the same power terms on the same side of the equation
The equation we are given here is
$3x + 4 = 5x - 10$
Now, adding $10\;$ on both the sides of the equation
$ \Rightarrow 3x + 4 + 10 = 5x - 10 + 10$
$ \Rightarrow 3x + 14 = 5x$
Now, subtracting $3x\;$ from both sides of the equation
$ \Rightarrow 3x - 3x + 14 = 5x - 3x$
$ \Rightarrow 14 = 5x - 3x$
Now, to explain the subtraction, let’s expand the terms $5x\;$ and $3x\;$ .
We know that $5x\;$ means $5$ times $x$ . Hence, expanding $5x\;$ as shown
$ \Rightarrow 5x = x + x + x + x + x$
Similarly, for $3x\;$ we can write
$ \Rightarrow 3x = x + x + x$
On subtracting them both we get,
$ \Rightarrow 14 = 2x$
Dividing both the sides by $2$ ,
$ \Rightarrow \dfrac{{14}}{2} = \dfrac{{2x}}{2}$
Factoring the numerator,
$ \Rightarrow \dfrac{{2 \times 7}}{2} = \dfrac{{2x}}{2}$
$ \Rightarrow x = 7$
Hence the solution for the given equation is $x = 7$.
Note: Another method for subtracting the terms with $x$ is by taking the common factor i.e. variable $x$ common and subtracting the numbers in the bracket. If one wants to check the accuracy of the solution, one can substitute the obtained value in the given equation and check if it satisfies the equation.
Putting $x = 7$ in the equation.
$ \Rightarrow 3x + 4 = 5x - 10$
$ \Rightarrow 3(7) + 4 = 5(7) - 10$
Now evaluate.
$ \Rightarrow 21 + 4 = 35 - 10$
$ \Rightarrow 25 = 25$
Since LHS=RHS, our answer is hence correct.
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