How do you solve \[3x+1=5x-10\]?
Answer
573k+ views
Hint: From the question given, we have been asked to solve \[3x+1=5x-10\]. We can solve the given equation from the question by using some simple transformations. First, we will shift the constants to the LHS and then the terms with the variable x to the RHS. We will then get the equation simplified and then we can solve it easily.
Complete step-by-step solution:
From the question given, we have been given that,
\[3x+1=5x-10\]
As we have already discussed earlier, we have to make some simple transformations to the above equation to get it simplified.
Shift \[10\] from the right hand side of the equation to the left hand side of the equation. By shifting \[10\] from right hand side of the equation to the left hand side of the equation, we get
\[\Rightarrow 3x+1+10=5x\]
Now, simplify the above equation further. By simplifying the above equation further, we get
\[\Rightarrow 3x+11=5x\]
Now, shift 3x from the left hand side of the equation to the right hand side of the equation. By shifting 3x from left hand side of the equation to the right hand side of the equation, we get
\[\Rightarrow 11=5x-3x\]
In the right hand side of the above equation, we can clearly see that there is a variable common in both the terms.
So, we know that if the variable is common in the terms, we can simply subtract the constants.
By doing this, we get
\[\Rightarrow 11=2x\]
Shift \[2\] from the right hand side of the equation to the left hand side of the equation. By shifting \[2\] from right hand side of the equation to the left hand side of the equation, we get
\[\Rightarrow x=\dfrac{11}{2}\]
Therefore, the given equation is solved.
Note: Students should be well aware of the transformations that have to be made to the given question to get the given question simplified very easily. Also, students should be very careful while applying the transformation to the given equation for example in transforming the equation by sending LHS to RHS in this case \[\Rightarrow 3x+1+10=5x\] \[\Rightarrow 11=5x-3x\] this is correct we should not take it as \[\Rightarrow 11=5x+3x\] it will give us wrong answer and also be very careful while doing the calculation part.
Complete step-by-step solution:
From the question given, we have been given that,
\[3x+1=5x-10\]
As we have already discussed earlier, we have to make some simple transformations to the above equation to get it simplified.
Shift \[10\] from the right hand side of the equation to the left hand side of the equation. By shifting \[10\] from right hand side of the equation to the left hand side of the equation, we get
\[\Rightarrow 3x+1+10=5x\]
Now, simplify the above equation further. By simplifying the above equation further, we get
\[\Rightarrow 3x+11=5x\]
Now, shift 3x from the left hand side of the equation to the right hand side of the equation. By shifting 3x from left hand side of the equation to the right hand side of the equation, we get
\[\Rightarrow 11=5x-3x\]
In the right hand side of the above equation, we can clearly see that there is a variable common in both the terms.
So, we know that if the variable is common in the terms, we can simply subtract the constants.
By doing this, we get
\[\Rightarrow 11=2x\]
Shift \[2\] from the right hand side of the equation to the left hand side of the equation. By shifting \[2\] from right hand side of the equation to the left hand side of the equation, we get
\[\Rightarrow x=\dfrac{11}{2}\]
Therefore, the given equation is solved.
Note: Students should be well aware of the transformations that have to be made to the given question to get the given question simplified very easily. Also, students should be very careful while applying the transformation to the given equation for example in transforming the equation by sending LHS to RHS in this case \[\Rightarrow 3x+1+10=5x\] \[\Rightarrow 11=5x-3x\] this is correct we should not take it as \[\Rightarrow 11=5x+3x\] it will give us wrong answer and also be very careful while doing the calculation part.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Advantages and disadvantages of science

Full form of STD, ISD and PCO

Give me the opposite gender of Duck class 8 english CBSE

What are gulf countries and why they are called Gulf class 8 social science CBSE

