
How do you solve \[3b-5-2b=5\]?
Answer
551.7k+ views
Hint: In this problem, we have to solve and find the value of b. We can first take the constant terms from the left-hand side to the right-hand side, so that the given problem will be easier to solve as we can have the variables to be simplified on one side and the constant on the other side. We can then simplify the equation to get the value of b.
Complete step by step answer:
We know that the given equation to be solved is,
\[3b-5-2b=5\]
We can now add the number 5 on both the left-hand side and the right-hand side of the equation, we get
\[\Rightarrow 3b-2b-5+5=5+5\]
We can now cancel the similar terms in the above step, we get
\[\Rightarrow 3b-2b=5+5\]
We can now simplify the above step by subtracting the terms with same variables in the left-hand side and the adding the terms in the right-hand side, we get
\[\begin{align}
& \Rightarrow b=5+5 \\
& \Rightarrow b=10 \\
\end{align}\]
Therefore, the value of b is 10.
Note:
Students make mistakes while adding or subtracting the correct numbers to the given equation on both the left-hand side and the right-hand side of the equation in order to cancel similar terms to get a simplified form so that we can find the value of the given unknown variable in the given equation. We can substitute the resulting value in the equation to check for the correct values.
We can substitute b = 10 in \[3b-5-2b=5\],
\[\begin{align}
& \Rightarrow 3\left( 10 \right)-5-2\left( 10 \right)=5 \\
& \Rightarrow 30-25=5 \\
\end{align}\]
Therefore, the values are correct.
Complete step by step answer:
We know that the given equation to be solved is,
\[3b-5-2b=5\]
We can now add the number 5 on both the left-hand side and the right-hand side of the equation, we get
\[\Rightarrow 3b-2b-5+5=5+5\]
We can now cancel the similar terms in the above step, we get
\[\Rightarrow 3b-2b=5+5\]
We can now simplify the above step by subtracting the terms with same variables in the left-hand side and the adding the terms in the right-hand side, we get
\[\begin{align}
& \Rightarrow b=5+5 \\
& \Rightarrow b=10 \\
\end{align}\]
Therefore, the value of b is 10.
Note:
Students make mistakes while adding or subtracting the correct numbers to the given equation on both the left-hand side and the right-hand side of the equation in order to cancel similar terms to get a simplified form so that we can find the value of the given unknown variable in the given equation. We can substitute the resulting value in the equation to check for the correct values.
We can substitute b = 10 in \[3b-5-2b=5\],
\[\begin{align}
& \Rightarrow 3\left( 10 \right)-5-2\left( 10 \right)=5 \\
& \Rightarrow 30-25=5 \\
\end{align}\]
Therefore, the values are correct.
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