
How do you solve \[2x-8x+1=9-10x\] ?
Answer
531.9k+ views
Hint: For the given question we are given to solve the equation \[2x-8x+1=9-10x\]. Now Let us bring all x terms at one side and constant terms to another side simultaneously. Then by solving the both LHS and RHS part we will get the answer.
Complete step by step solution:
For the given equation first we have to subtract x coefficient from the equation which is there on left hand side
\[2x-8x+1=9-10x\]
After subtraction of x coefficient of the equation on to the left hand side
\[\Rightarrow -6x+1=9-10x\]
And then we have to send all the x coefficient of the equation on to the left hand side
\[\Rightarrow -6x+10x+1=9\]
After sending all the x coefficients of the equation to the left hand side. Then we have to send all the variables of the equation on to the right hand side
\[\Rightarrow -6x+10x=9-1\]
And then we have to continue the problem as per the instructions by adding and subtracting the x coefficient of the equation
\[\Rightarrow 4x=9-1\]
And then we have to continue the problem as per the instructions by adding and subtracting the variables of the equation
\[\Rightarrow 4x=8\]
\[\Rightarrow x=\dfrac{8}{4}\]
\[\Rightarrow x=2\]
Therefore, the numerical of above this is the exact solution of the given problem
Note: As we can see that our answer is ‘2’. Now we have to check our answer by substituting the value of ‘x’ in the given equation i.e. \[2x-8x+1=9-10x\]. If we get the answer like LHS=RHS then we can confirm that our answer is correct. We should be careful and be aware of sign conversion.
Complete step by step solution:
For the given equation first we have to subtract x coefficient from the equation which is there on left hand side
\[2x-8x+1=9-10x\]
After subtraction of x coefficient of the equation on to the left hand side
\[\Rightarrow -6x+1=9-10x\]
And then we have to send all the x coefficient of the equation on to the left hand side
\[\Rightarrow -6x+10x+1=9\]
After sending all the x coefficients of the equation to the left hand side. Then we have to send all the variables of the equation on to the right hand side
\[\Rightarrow -6x+10x=9-1\]
And then we have to continue the problem as per the instructions by adding and subtracting the x coefficient of the equation
\[\Rightarrow 4x=9-1\]
And then we have to continue the problem as per the instructions by adding and subtracting the variables of the equation
\[\Rightarrow 4x=8\]
\[\Rightarrow x=\dfrac{8}{4}\]
\[\Rightarrow x=2\]
Therefore, the numerical of above this is the exact solution of the given problem
Note: As we can see that our answer is ‘2’. Now we have to check our answer by substituting the value of ‘x’ in the given equation i.e. \[2x-8x+1=9-10x\]. If we get the answer like LHS=RHS then we can confirm that our answer is correct. We should be careful and be aware of sign conversion.
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