Question

How do you solve \[2x + 3x - 2x = 15\] ?

Answer 1

Hint: The equation is an algebraic equation, where the algebraic equation is the combination of constants and variables. To solve the above algebraic equation, we use the tables of multiplication and we can find the value of x.

Complete step by step solution:
The algebraic expression is an expression which consists of variables and is consistent with the arithmetic operations. The above equation is a linear equation where the linear equation is defined as the equations are of the first order. These equations are defined for lines in the coordinate system. To solve this linear equation, we apply simple methods. Since by solving these types of equations we get only one value.
Now we solve the given equation, let us consider the equation
 \[2x + 3x - 2x = 15\]
The 2x and -2x will gets cancels and the equation is written as
 \[ \Rightarrow 3x = 15\]
Now divide the equation by 3 we get
 \[ \Rightarrow x = 5\]
Therefore, the value of x is 5.
We can also solve this by another method. Now consider the equation
 \[2x + 3x - 2x = 15\]
Take x as common and it is written as
 \[x(2 + 3 - 2) = 15\]
On simplifying the terms which are in braces we get
 \[ \Rightarrow 3x = 15\]
Take 15 to LHS and we get
 \[ \Rightarrow 3x - 15 = 0\]
Take 3 as a common we get
 \[3(x - 5) = 0\]
 \[ \Rightarrow x - 5 = 0\]
Therefore, we have \[x = 5\]
Hence we have solved the given equation
Therefore, the value of x is 5.
If we solve the equation by the different methods the result obtained will be the same.
So, the correct answer is “\[x = 5\] ”.

Note: The algebraic equation or an expression is a combination of variables and constants, it also contains the coefficient. The alphabets are known as variables. The x, y, z etc., are called as variables. The numerals are known as constants. The numeral of a variable is known as co-efficient. We have 3 types of algebraic expressions namely monomial expression, binomial expression and polynomial expression. By using the tables of multiplication, we can solve the equation.