Question

How do you solve $2x+18-1=33$?

Answer 1

Hint: In this problem we have to solve the given equation i.e., we need to calculate the value of $x$ where the value of $x$ satisfies the given equation. To solve the given equation, we will apply the reverse arithmetic operations for the arithmetic operations we have in the equation. We can observe that addition, subtraction, multiplication operations are present in the given equation, so we will apply the reverse operations one by one to solve the equation.

Complete step-by-step solution:
Given equation, $2x+18-1=33$.
Subtracting the one from eighteen then we will get seventeen as a result. Mathematically we can write it as $18-1=17$. Substituting this value in the above equation, then we will get
$2x+17=33$
We can observe that in the above equation $17$ is in addition. To solve the equation, we will apply reverse operation for addition which is subtraction. So, subtracting $17$ on both sides of the above equation, then we will get
$\Rightarrow 2x+17-17=33-17$
We know that $+a-a=0$, then we will get
$\Rightarrow 2x=33-17$
We have the value $33-17=16$, then we will get
$\Rightarrow 2x=16$
In the above equation we can observe that $2$ is in multiplication. To solve the equation, we will apply reverse operation which is division. So, dividing the above equation with $2$ on both sides of the above equation, then we will get
$\Rightarrow \dfrac{2x}{2}=\dfrac{16}{2}$
Simplifying the above equation, then we will get
$\Rightarrow x=8$
Hence the solution of the given equation $2x+18-1=33$ is $x=8$.

Note: We can check whether the obtained solution is correct or wrong by plugging the obtained solution in the given equation. Substituting the $x=8$ in the above equation, then we will get
$\begin{align}
  & 2x+18-1=33 \\
 & \Rightarrow 2\left( 8 \right)+17=33 \\
 & \Rightarrow 16+17=33 \\
 & \Rightarrow 33=33 \\
 & \Rightarrow LHS=RHS \\
\end{align}$
So, the obtained solution is correct.