Question

How do you solve $-26-2x=10-8x$ ?

Answer 1

Hint: The given equation is a linear equation in one variable, we can solve it by bringing all x to one side and all constant to another side. Then we can divide both LHS and RHS by the coefficient of x to get the value of x. The equation has one variable, so one equation is enough to solve it.

Complete step by step solution:
The given equation in the question is $-26-2x=10-8x$ which is a linear equation in one variable
Now we can bring all the x to LHS and all the constant to RHS
Adding 8x to both LHS and RHS we get -26 + 6x = 10
Now adding 26 to both sides we get 6x = 36
Dividing both LHS and RHS by 6 we get x = 6
So the value of x = 11 is the solution of $-26-2x=10-8x$

Note: The equation given in the question was a linear equation in one variable, so one equation is enough to solve it. If there are n unknown variables then minimum n linear equations are required to evaluate all the unknown variables. If the delta value of the system of equation is 0 then the system is inconsistent that means there may be infinitely many solutions for the system of equation or there may be no solution exist for the system of equation.