
How do you solve -18=6t?
Answer
543.3k+ views
Hint: This question belongs to the topic algebra. So, we should have better knowledge in algebra. We should know how to solve the equation. In solving this question, first, we will take all the values to the left side of the equation. After that, we will find the value of t by taking out the common factors.
Complete step by step answer:
Let us solve this question.
In this question, we have asked to solve the equation -18=6t. That means we have asked to find the value of t.
First, writing below the given equation
-18=6t
By taking all the constants and variables to the left side of the equation and zero to the right side of the equation, we get
\[\Rightarrow \]-18-6t=0
We can take a common factor herein above equation, which is negative
\[\Rightarrow \]-(18+6t)=0
The above equation can also be written as
\[\Rightarrow \]18+6t=0
Now, we know that 6 is a factor of 18. So, we can write the above as
\[\Rightarrow \]6(3+t)=0
We can write the above equation as
\[\Rightarrow \]3+t=0
So, we can solve the above equation and get the value of t.
Hence, the last can be written as
\[\Rightarrow \]t=-3
Therefore, we get that the value of t is -3.
Note:
We have an alternate method to solve this question. We can solve this question just by dividing.
So, the equation is
-18=6t
Or, we can the above equation as
\[\Rightarrow \]6t=-18
Now, we will divide 6 into both sides of the equation or we can say that we are going to multiply 6 on both sides of the denominator.
\[\Rightarrow \dfrac{6t}{6}=\dfrac{-18}{6}\]
As we know that prime factors of 6 are 2 and 3 and the prime factors of 18 are 2, 3, and 3.
So, we can write the above equation as
\[\Rightarrow \dfrac{2\times 3\times t}{2\times 3}=\dfrac{-2\times 3\times 3}{2\times 3}\]
Hence, 2 and 3 are canceled out in the numerator and denominator of both sides of the equation.
\[\Rightarrow \]t=-3
Hence, we can see that we are getting the same value from both methods.
Complete step by step answer:
Let us solve this question.
In this question, we have asked to solve the equation -18=6t. That means we have asked to find the value of t.
First, writing below the given equation
-18=6t
By taking all the constants and variables to the left side of the equation and zero to the right side of the equation, we get
\[\Rightarrow \]-18-6t=0
We can take a common factor herein above equation, which is negative
\[\Rightarrow \]-(18+6t)=0
The above equation can also be written as
\[\Rightarrow \]18+6t=0
Now, we know that 6 is a factor of 18. So, we can write the above as
\[\Rightarrow \]6(3+t)=0
We can write the above equation as
\[\Rightarrow \]3+t=0
So, we can solve the above equation and get the value of t.
Hence, the last can be written as
\[\Rightarrow \]t=-3
Therefore, we get that the value of t is -3.
Note:
We have an alternate method to solve this question. We can solve this question just by dividing.
So, the equation is
-18=6t
Or, we can the above equation as
\[\Rightarrow \]6t=-18
Now, we will divide 6 into both sides of the equation or we can say that we are going to multiply 6 on both sides of the denominator.
\[\Rightarrow \dfrac{6t}{6}=\dfrac{-18}{6}\]
As we know that prime factors of 6 are 2 and 3 and the prime factors of 18 are 2, 3, and 3.
So, we can write the above equation as
\[\Rightarrow \dfrac{2\times 3\times t}{2\times 3}=\dfrac{-2\times 3\times 3}{2\times 3}\]
Hence, 2 and 3 are canceled out in the numerator and denominator of both sides of the equation.
\[\Rightarrow \]t=-3
Hence, we can see that we are getting the same value from both methods.
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