
How do you solve $ 17 = 5y - 3? $
Answer
520.8k+ views
Hint: Take the given expression move term with a variable on the right hand side of the equation and the constants on the left hand side of the equation.
Complete step by step solution:
Take the given expression: $ 17 = 5y - 3 $
The above equation can be re-written as –
$ 5y - 3 = 17 $
Move the constant from the left hand side of the equation on the right hand side of the equation. When you move any term from one side to the opposite side then the sign of the term also changes. Negative term becomes positive term.
$ 5y = 17 + 3 $
Simplify the above expression by finding the sum of terms on the right hand side of the equation.
$ 5y = 20 $
Term multiplicative on one side if moved to the opposite side then it goes to the denominator.
$ y = \dfrac{{20}}{5} $
Find the factors for the term on the numerator on the right hand side of the above equation.
$ y = \dfrac{{5 \times 4}}{5} $
Common multiple from the numerator and the denominator cancels each other. Therefore, remove from the numerator and the denominator.
$ \Rightarrow y = 4 $
This is the required solution.
So, the correct answer is “ y = 4”.
Note: Always remember that when you move any term from one side to another then the sign of the term also changes. Positive terms become negative and vice-versa. Be careful about the sign convention while simplifying.
Complete step by step solution:
Take the given expression: $ 17 = 5y - 3 $
The above equation can be re-written as –
$ 5y - 3 = 17 $
Move the constant from the left hand side of the equation on the right hand side of the equation. When you move any term from one side to the opposite side then the sign of the term also changes. Negative term becomes positive term.
$ 5y = 17 + 3 $
Simplify the above expression by finding the sum of terms on the right hand side of the equation.
$ 5y = 20 $
Term multiplicative on one side if moved to the opposite side then it goes to the denominator.
$ y = \dfrac{{20}}{5} $
Find the factors for the term on the numerator on the right hand side of the above equation.
$ y = \dfrac{{5 \times 4}}{5} $
Common multiple from the numerator and the denominator cancels each other. Therefore, remove from the numerator and the denominator.
$ \Rightarrow y = 4 $
This is the required solution.
So, the correct answer is “ y = 4”.
Note: Always remember that when you move any term from one side to another then the sign of the term also changes. Positive terms become negative and vice-versa. Be careful about the sign convention while simplifying.
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