Question

How do you solve $15 - \dfrac{x}{8} = 4$ ?

Answer 1

Hint: To solve such questions first subtract the number $\;15$ from both sides of the given equation. Then multiply by $8$ on both sides of the equation. After that, cancel the common terms in LHS and RHS. This way we will get the required solution.

Complete step by step answer:
Given the equation $15 - \dfrac{x}{8} = 4$ .
Here it is asked to find the solution to this equation.
Start by subtracting $\;15$ from both sides of the given equation. That is,
$15 - \dfrac{x}{8} - 15 = 4 - 15$
$\Rightarrow 0 - \dfrac{x}{8} = - 11$
Cancel the negative sign from both sides of the equation. That is,
$\dfrac{x}{8} = 11$
Next multiply by $8$ on both sides of the above equation. That is,
$\dfrac{x}{8} \times 8 = 11 \times 8$
Cancel out the common terms in the numerator and denominator of the LHS and also multiplying the RHS we get,
$x = 88$

Therefore, the solution of the equation $15 - \dfrac{x}{8} = 4$ is $x = 88$ .

Additional information:
Variables can be defined as a quantity that is not fixed. An algebraic expression can be made up of variables, constants, and operators. An equation can be defined as one which allows only a specific value of a variable. For a given term to be an equation, the left-hand side should be equal to the right-hand side. If they are not equal then it cannot be an equation. The value of the variable, which we get by solving the equation, is known as the solution of the equation.

Note: Always start by canceling out the terms on the left-hand side of the given equation so that the equation becomes more simplified. It is possible to check whether the obtained solution is right or not by substituting it in the given equation.