
How do you simplify \[{{i}^{752}}\]?
Answer
541.5k+ views
Hint: In this problem, we have to simplify the given imaginary part. We should know that any negative terms inside the square root is equal to an imaginary part, which will be a complex number. We can write it as \[i=\sqrt{-1}\]. Using this we can find the value of \[{{i}^{4}}\]. We can then split the given power term in terms of multiplication of 4 to find the value of the given imaginary part.
Complete step by step solution:
We know that the given imaginary part to be simplified is \[{{i}^{752}}\].
We know that any negative terms inside the square root is equal to an imaginary part, which will be a complex number.
We can write it as,
\[i=\sqrt{-1}\].
We can now write the square term of \[i\], we get
\[\Rightarrow {{i}^{2}}={{\left( \sqrt{-1} \right)}^{2}}=-1\]
We can now write the fourth power of \[i\], using the above step, we get
\[\begin{align}
& \Rightarrow {{\left( {{i}^{2}} \right)}^{2}}={{\left( -1 \right)}^{2}} \\
& \Rightarrow {{i}^{4}}=1 \\
\end{align}\]
Now we can write the given power as,
\[\Rightarrow 752=188\times 4\]
We can write the given imaginary part as,
\[\Rightarrow {{i}^{752}}={{\left( {{i}^{4}} \right)}^{188}}\]
We can now substitute \[{{i}^{4}}=1\], we get
\[\Rightarrow {{i}^{752}}={{1}^{188}}=1\]
Since anything to the power 1 is one itself.
Therefore, the value of \[{{i}^{752}}\] is 1.
Note: Students make mistakes while finding the value of the fourth power of the imaginary part \[i\]. We should always remember that the complex number exists when we have a negative term inside the root, where the imaginary part occurs. We should also remember that anything to the power one is one itself.
Complete step by step solution:
We know that the given imaginary part to be simplified is \[{{i}^{752}}\].
We know that any negative terms inside the square root is equal to an imaginary part, which will be a complex number.
We can write it as,
\[i=\sqrt{-1}\].
We can now write the square term of \[i\], we get
\[\Rightarrow {{i}^{2}}={{\left( \sqrt{-1} \right)}^{2}}=-1\]
We can now write the fourth power of \[i\], using the above step, we get
\[\begin{align}
& \Rightarrow {{\left( {{i}^{2}} \right)}^{2}}={{\left( -1 \right)}^{2}} \\
& \Rightarrow {{i}^{4}}=1 \\
\end{align}\]
Now we can write the given power as,
\[\Rightarrow 752=188\times 4\]
We can write the given imaginary part as,
\[\Rightarrow {{i}^{752}}={{\left( {{i}^{4}} \right)}^{188}}\]
We can now substitute \[{{i}^{4}}=1\], we get
\[\Rightarrow {{i}^{752}}={{1}^{188}}=1\]
Since anything to the power 1 is one itself.
Therefore, the value of \[{{i}^{752}}\] is 1.
Note: Students make mistakes while finding the value of the fourth power of the imaginary part \[i\]. We should always remember that the complex number exists when we have a negative term inside the root, where the imaginary part occurs. We should also remember that anything to the power one is one itself.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

