How do you simplify \[\dfrac{1}{{{i^3}}}\] ?
Answer
575.4k+ views
Hint: Here in this question, we have to simplify the given number, the given number in the form of fraction and in the denominator we have a ‘ \[{i^3}\] ’ where i represent the imaginary number. By using the properties on imaginary numbers and knowing i raise to 4n is equal to 1 and on further simplification by using the value of i, we obtain the required solution for the question
Complete step-by-step answer:
Imaginary numbers are numbers that are not real or An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit I which is defined by its property. \[i = \sqrt { - 1} \] or \[{i^2} = - 1\] . The imaginary numbers are the numbers when squared it gives the negative result. In other words, imaginary numbers are defined as the square root of the negative numbers where it does not have a definite value, i.e., the square of imaginary number \[ai\] is \[ - a\] .
Consider the given fraction
\[ \Rightarrow \dfrac{1}{{{i^3}}}\]
It can be written as
\[ \Rightarrow \dfrac{1}{{i \cdot i \cdot i}}\]
As we know the value of imaginary number i is \[i = \sqrt { - 1} \] , then
\[ \Rightarrow \dfrac{1}{{\sqrt { - 1} \cdot \sqrt { - 1} \cdot \sqrt { - 1} }}\]
On multiplying,
\[ \Rightarrow \dfrac{1}{{{{\left( {\sqrt { - 1} } \right)}^2} \cdot \sqrt { - 1} }}\]
\[ \Rightarrow \dfrac{1}{{ - 1 \cdot \sqrt { - 1} }}\]
On further simplification we have
\[ \Rightarrow - \dfrac{1}{{\sqrt { - 1} }}\]
Rationalise the denominator by multiplying both numerator and denominator by \[\sqrt { - 1} \] .
\[ \Rightarrow - \dfrac{1}{{\sqrt { - 1} }} \times \dfrac{{\sqrt { - 1} }}{{\sqrt { - 1} }}\]
\[ \Rightarrow - \dfrac{{\sqrt { - 1} }}{{{{\left( {\sqrt { - 1} } \right)}^2}}}\]
\[ \Rightarrow - \dfrac{{\sqrt { - 1} }}{{ - 1}}\]
Therefore we have
\[ \Rightarrow \sqrt { - 1} \]
As we know \[\sqrt { - 1} \] is the value of i
\[\therefore \,\,\dfrac{1}{{{i^3}}} = \sqrt 1 = i\]
Hence, after simplification the value of \[\dfrac{1}{{{i^3}}}\] is \[\sqrt { - 1} \] or \[i\] .
So, the correct answer is “ \[i\] ”.
Note: The complex number is having the real part and imaginary part. The real part is the whole number and the imaginary number is represented by i. and we can also multiply the imaginary number. The imaginary number i is defined as \[\sqrt { - 1} \] . There is a square root for the negative number so we consider it as i.
Complete step-by-step answer:
Imaginary numbers are numbers that are not real or An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit I which is defined by its property. \[i = \sqrt { - 1} \] or \[{i^2} = - 1\] . The imaginary numbers are the numbers when squared it gives the negative result. In other words, imaginary numbers are defined as the square root of the negative numbers where it does not have a definite value, i.e., the square of imaginary number \[ai\] is \[ - a\] .
Consider the given fraction
\[ \Rightarrow \dfrac{1}{{{i^3}}}\]
It can be written as
\[ \Rightarrow \dfrac{1}{{i \cdot i \cdot i}}\]
As we know the value of imaginary number i is \[i = \sqrt { - 1} \] , then
\[ \Rightarrow \dfrac{1}{{\sqrt { - 1} \cdot \sqrt { - 1} \cdot \sqrt { - 1} }}\]
On multiplying,
\[ \Rightarrow \dfrac{1}{{{{\left( {\sqrt { - 1} } \right)}^2} \cdot \sqrt { - 1} }}\]
\[ \Rightarrow \dfrac{1}{{ - 1 \cdot \sqrt { - 1} }}\]
On further simplification we have
\[ \Rightarrow - \dfrac{1}{{\sqrt { - 1} }}\]
Rationalise the denominator by multiplying both numerator and denominator by \[\sqrt { - 1} \] .
\[ \Rightarrow - \dfrac{1}{{\sqrt { - 1} }} \times \dfrac{{\sqrt { - 1} }}{{\sqrt { - 1} }}\]
\[ \Rightarrow - \dfrac{{\sqrt { - 1} }}{{{{\left( {\sqrt { - 1} } \right)}^2}}}\]
\[ \Rightarrow - \dfrac{{\sqrt { - 1} }}{{ - 1}}\]
Therefore we have
\[ \Rightarrow \sqrt { - 1} \]
As we know \[\sqrt { - 1} \] is the value of i
\[\therefore \,\,\dfrac{1}{{{i^3}}} = \sqrt 1 = i\]
Hence, after simplification the value of \[\dfrac{1}{{{i^3}}}\] is \[\sqrt { - 1} \] or \[i\] .
So, the correct answer is “ \[i\] ”.
Note: The complex number is having the real part and imaginary part. The real part is the whole number and the imaginary number is represented by i. and we can also multiply the imaginary number. The imaginary number i is defined as \[\sqrt { - 1} \] . There is a square root for the negative number so we consider it as i.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

How many bones are in the spine class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

