How do you simplify 8 ( m – 5 ) + 6 m ?
Answer
577.5k+ views
Hint: To simplify the following equation it is required to open the terms in the brackets by multiplying the 8 with each term inside the bracket separately and then separate the terms with the variables and similarly separate the constant terms and group them. Now add the like terms i.e add the terms with variables separately and add all constant terms to get the simplified form the given equation.
Complete step by step solution:
The given equation is
8 ( m – 5 ) + 6 m
Firstly we should open the bracket as below,
\[\Rightarrow \] 8 m – 40 + 6 m
Now, writing the like terms together, we get
\[\Rightarrow \] 8 m + 6 m – 40
Taking variable common from the terms with variable, we get
\[\Rightarrow \] ( 8 + 6 ) m – 40
Adding the coefficients of the variable terms, we get
\[\Rightarrow \] ( 14 ) m – 40
\[\Rightarrow \] 14 m – 40
So, the simplified form of the given equation 8 ( m – 5 ) + 6 m is calculated to be 14 m – 40 from the above simplification shown.
Note: The basic operation of opening the bracket first should be known first as it is done by using B O D M A S rule. The mistake can happen while adding the terms, as sometimes we may end up adding unlike terms as a variable term with a constant term and so caution should be taken. This also can be solved just by observation and making out which are variable terms and constant terms. And make sure you never add unlike terms while solving. It results in a wrong answer.
Complete step by step solution:
The given equation is
8 ( m – 5 ) + 6 m
Firstly we should open the bracket as below,
\[\Rightarrow \] 8 m – 40 + 6 m
Now, writing the like terms together, we get
\[\Rightarrow \] 8 m + 6 m – 40
Taking variable common from the terms with variable, we get
\[\Rightarrow \] ( 8 + 6 ) m – 40
Adding the coefficients of the variable terms, we get
\[\Rightarrow \] ( 14 ) m – 40
\[\Rightarrow \] 14 m – 40
So, the simplified form of the given equation 8 ( m – 5 ) + 6 m is calculated to be 14 m – 40 from the above simplification shown.
Note: The basic operation of opening the bracket first should be known first as it is done by using B O D M A S rule. The mistake can happen while adding the terms, as sometimes we may end up adding unlike terms as a variable term with a constant term and so caution should be taken. This also can be solved just by observation and making out which are variable terms and constant terms. And make sure you never add unlike terms while solving. It results in a wrong answer.
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