
How do you simplify \[(5 + 3i)(3 - i)\]?
Answer
462.6k+ views
Hint: We simplify or solve the product given by multiplying numbers in the first bracket with the complete second bracket one by one. We multiply the given factors or brackets by opening the terms and then write the quadratic equation formed by multiplication. Substitute the value of \[{i^2} = - 1\] and pair the terms with \[i\].
* When we have to multiply the brackets like \[(a + b)(c + d)\] then we multiply the second bracket by a first and then by b i.e. \[a(c + d) + b(c + d)\]. Then we multiply each term outside the bracket with terms inside the bracket one by one i.e. a with c, a with d, b with c and b with d i.e. \[ac + ad + bc + bd\]
Complete step-by-step answer:
We are given the product \[(5 + 3i)(3 - i)\]
We will simplify the product by multiplying terms from first bracket to second bracket one by one.
\[ \Rightarrow (5 + 3i)(3 - i) = 5(3 - i) + 3i(3 - i)\]
Now we multiply each term outside the bracket with terms inside the bracket one by one
\[ \Rightarrow (5 + 3i)(3 - i) = \left( {5 \times 3} \right) + \left( {5 \times ( - i)} \right) + \left( {3i \times 3} \right) + \left( {3i \times ( - i)} \right)\]
Calculate the products on right side of the equation
\[ \Rightarrow (5 + 3i)(3 - i) = 15 - 5i + 9i - 3{i^2}\]
Add the terms having same coefficient or variable associated with them
\[ \Rightarrow (5 + 3i)(3 - i) = 15 + 4i - 3{i^2}\]
Now we know that \[{i^2} = - 1\]
Substitute the value of \[{i^2} = - 1\] in right hand side of the equation
\[ \Rightarrow (5 + 3i)(3 - i) = 15 + 4i - 3( - 1)\]
\[ \Rightarrow (5 + 3i)(3 - i) = 15 + 4i + 3\]
Add the constant terms on right hand side of the equation
\[ \Rightarrow (5 + 3i)(3 - i) = 18 + 4i\]
\[\therefore \]Solution of \[(5 + 3i)(3 - i)\] is \[18 + 4i\]
Note:
Many students make the mistake of writing the quadratic equation formed without simplifying i.e. without even adding the terms or combining the terms with the same coefficient or variable associated with it. It is compulsory to substitute the value of \[{i^2} = - 1\] as we know its value exists. Keep in mind the answer should be as much simplified as it can be.
* When we have to multiply the brackets like \[(a + b)(c + d)\] then we multiply the second bracket by a first and then by b i.e. \[a(c + d) + b(c + d)\]. Then we multiply each term outside the bracket with terms inside the bracket one by one i.e. a with c, a with d, b with c and b with d i.e. \[ac + ad + bc + bd\]
Complete step-by-step answer:
We are given the product \[(5 + 3i)(3 - i)\]
We will simplify the product by multiplying terms from first bracket to second bracket one by one.
\[ \Rightarrow (5 + 3i)(3 - i) = 5(3 - i) + 3i(3 - i)\]
Now we multiply each term outside the bracket with terms inside the bracket one by one
\[ \Rightarrow (5 + 3i)(3 - i) = \left( {5 \times 3} \right) + \left( {5 \times ( - i)} \right) + \left( {3i \times 3} \right) + \left( {3i \times ( - i)} \right)\]
Calculate the products on right side of the equation
\[ \Rightarrow (5 + 3i)(3 - i) = 15 - 5i + 9i - 3{i^2}\]
Add the terms having same coefficient or variable associated with them
\[ \Rightarrow (5 + 3i)(3 - i) = 15 + 4i - 3{i^2}\]
Now we know that \[{i^2} = - 1\]
Substitute the value of \[{i^2} = - 1\] in right hand side of the equation
\[ \Rightarrow (5 + 3i)(3 - i) = 15 + 4i - 3( - 1)\]
\[ \Rightarrow (5 + 3i)(3 - i) = 15 + 4i + 3\]
Add the constant terms on right hand side of the equation
\[ \Rightarrow (5 + 3i)(3 - i) = 18 + 4i\]
\[\therefore \]Solution of \[(5 + 3i)(3 - i)\] is \[18 + 4i\]
Note:
Many students make the mistake of writing the quadratic equation formed without simplifying i.e. without even adding the terms or combining the terms with the same coefficient or variable associated with it. It is compulsory to substitute the value of \[{i^2} = - 1\] as we know its value exists. Keep in mind the answer should be as much simplified as it can be.
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