How do you simplify ${(2{x^3})^4}$ ?
Answer
574.8k+ views
Hint:We will start by using the following exponent rule:
${({x^a})^b} = {x^{a \times b}}$. Mention all the terms. Then reduce the terms until they cannot be reduced any further. We will also use the rule ${x^a} = \dfrac{1}{{{x^{ - a}}}}$ to simplify the terms further.
Complete step by step answer:
We will start off by applying the exponent rule given by, ${({x^a})^b}
= {x^{a \times b}}$.
\[
= {(2{x^3})^4} \\
= {2^4}{x^{3 \times 4}} \\
\]
Now we will simplify the terms which are within the parenthesis.
\[
= {2^4}{x^{3 \times 4}} \\
= 16{x^{12}} \\
\]
Hence, the value of the expression ${(2{x^3})^4}$ is \[16{x^{12}}\].
Additional Information: The power rule tells us that to raise a power to a power, just multiply the exponents. The quotient rule tells us that we can divide two powers with the same base by subtracting the exponents. If any negative number is raised to a negative power equals its reciprocal raised to the opposite power. Any number raised to a power one equals itself. In the exponent product rule, when multiplying two powers that have the same base, you can add the exponents. A negative exponent means divides, because the opposite of multiplying is dividing. A fractional exponent means to take the ${n^{th}}$root. A quotient rule tells us that we can divide two powers with the same base by subtracting the exponents.
Note: While applying the rule, ${({x^a})^b} = {x^{a \times b}}$ make sure that you have considered terms properly so that the terms should get easier to solve. Also, while applying the rule, ${x^a} = \dfrac{1}{{{x^{ - a}}}}$ pay more attention to the sign of the powers. If the sign is missed whole the problem can be incorrect. Also, remember that the negative exponent means to divide, as the opposite of multiplying is dividing.
${({x^a})^b} = {x^{a \times b}}$. Mention all the terms. Then reduce the terms until they cannot be reduced any further. We will also use the rule ${x^a} = \dfrac{1}{{{x^{ - a}}}}$ to simplify the terms further.
Complete step by step answer:
We will start off by applying the exponent rule given by, ${({x^a})^b}
= {x^{a \times b}}$.
\[
= {(2{x^3})^4} \\
= {2^4}{x^{3 \times 4}} \\
\]
Now we will simplify the terms which are within the parenthesis.
\[
= {2^4}{x^{3 \times 4}} \\
= 16{x^{12}} \\
\]
Hence, the value of the expression ${(2{x^3})^4}$ is \[16{x^{12}}\].
Additional Information: The power rule tells us that to raise a power to a power, just multiply the exponents. The quotient rule tells us that we can divide two powers with the same base by subtracting the exponents. If any negative number is raised to a negative power equals its reciprocal raised to the opposite power. Any number raised to a power one equals itself. In the exponent product rule, when multiplying two powers that have the same base, you can add the exponents. A negative exponent means divides, because the opposite of multiplying is dividing. A fractional exponent means to take the ${n^{th}}$root. A quotient rule tells us that we can divide two powers with the same base by subtracting the exponents.
Note: While applying the rule, ${({x^a})^b} = {x^{a \times b}}$ make sure that you have considered terms properly so that the terms should get easier to solve. Also, while applying the rule, ${x^a} = \dfrac{1}{{{x^{ - a}}}}$ pay more attention to the sign of the powers. If the sign is missed whole the problem can be incorrect. Also, remember that the negative exponent means to divide, as the opposite of multiplying is dividing.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Which among the following are examples of coming together class 11 social science CBSE

