How do you simplify $10{}^\circ \times 0.23?$
Answer
607.8k+ views
Hint: (1) Here we see that the given equation is in the form of exponential.
(2) Exponents are numbers which represent how many times use that number in multiplication. It is mainly written in \[{{8}^{2}}=8\times 8=64\](the exponent ‘2’ says to use the term ‘8’ two times in a multiplication.
(3) Use the rule for exponents:
i.e. $a{}^\circ =1,e{}^\circ =1$
Remember that a numbers multiplies can also be expressed exponential form:
$\Rightarrow $e.g. $9{}^\circ =1$
Complete Step by Step solution:
Given: $10{}^\circ \times 0.23$
Here, as we know that $10{}^\circ $ is an exponential form.
Power of $10,$ is as many number $10s$ as indicated by the exponent multiplied together ${{10}^{n}}=10{}^\circ $
Where, $n=0$ the power of $10$ is $1$.
$\Rightarrow 10{}^\circ =1$
We will process the steps to simplify.
$\Rightarrow 1\times 0.23$ (any number multiplied $'1'$ is will be same number)
$\Rightarrow $$=0.23$
Additional Information:
(1) If the power is positive, move the decimal point to the right, but if the power is negative, then move the decimal point to the left.
For example:
(i) $1.23\times {{10}^{3}}=1234.5$
(ii) $1.23\times {{10}^{-4}}=0.00012345$
Notation we can express very large or small numbers by powers of so that the values are more easily understood.
$\Rightarrow $i.e. e.g. $9{}^\circ =1,$ ${{9}^{1}}=9$, ${{9}^{2}}=81$
Note:
(1) Use scientific notation or exponential form in the given question otherwise it is not possible to solve the problem. Scientific notation is defined as expressing a very large or small number by powers of ten so that the values are more easily understood.
(2) Remember that number multiplies can be expressed as
For example:
$\Rightarrow $$10{}^\circ =1$
That $10{}^\circ =0$ cannot be possible.
(3) Also remember that any number or integer is in multiplication with 1, therefore its answer will remain the same as it is there will be no change in its value.
(2) Exponents are numbers which represent how many times use that number in multiplication. It is mainly written in \[{{8}^{2}}=8\times 8=64\](the exponent ‘2’ says to use the term ‘8’ two times in a multiplication.
(3) Use the rule for exponents:
i.e. $a{}^\circ =1,e{}^\circ =1$
Remember that a numbers multiplies can also be expressed exponential form:
$\Rightarrow $e.g. $9{}^\circ =1$
Complete Step by Step solution:
Given: $10{}^\circ \times 0.23$
Here, as we know that $10{}^\circ $ is an exponential form.
Power of $10,$ is as many number $10s$ as indicated by the exponent multiplied together ${{10}^{n}}=10{}^\circ $
Where, $n=0$ the power of $10$ is $1$.
$\Rightarrow 10{}^\circ =1$
We will process the steps to simplify.
$\Rightarrow 1\times 0.23$ (any number multiplied $'1'$ is will be same number)
$\Rightarrow $$=0.23$
Additional Information:
(1) If the power is positive, move the decimal point to the right, but if the power is negative, then move the decimal point to the left.
For example:
(i) $1.23\times {{10}^{3}}=1234.5$
(ii) $1.23\times {{10}^{-4}}=0.00012345$
Notation we can express very large or small numbers by powers of so that the values are more easily understood.
$\Rightarrow $i.e. e.g. $9{}^\circ =1,$ ${{9}^{1}}=9$, ${{9}^{2}}=81$
Note:
(1) Use scientific notation or exponential form in the given question otherwise it is not possible to solve the problem. Scientific notation is defined as expressing a very large or small number by powers of ten so that the values are more easily understood.
(2) Remember that number multiplies can be expressed as
For example:
$\Rightarrow $$10{}^\circ =1$
That $10{}^\circ =0$ cannot be possible.
(3) Also remember that any number or integer is in multiplication with 1, therefore its answer will remain the same as it is there will be no change in its value.
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