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# How do you graph $y=\dfrac{1}{2}$.

Last updated date: 14th Sep 2024
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Hint: The above given question is a graph of linear equations in one variable. Since, we know that the slope intercept form of the line equation is given as y = mx + c, where m is the slope of the line and c is the y-intercept. In the given equation $y=\dfrac{1}{2}$, we have m = 0 and $c=\dfrac{1}{2}$ . So, the line $y=\dfrac{1}{2}$ will be parallel to x-axis as slope is equal to 0 and intersect y-axis at coordinate $\left( 0,\dfrac{1}{2} \right)$.

Now, we will compare the equation $y=\dfrac{1}{2}$ with the general equation y = mx + c.
After comparing we will get: m = 0 and $c=\dfrac{1}{2}$.
So, the slope of the line $y=\dfrac{1}{2}$ is equal to 0, and the y-intercept is equal to $\dfrac{1}{2}$.
Since slope of the line is equal to 0, hence the line will be parallel to the x-axis and also y-intercept is equal to $\dfrac{1}{2}$. So, it will intersect the y-axis at the point $\left( 0,\dfrac{1}{2} \right)$.
So, the required graph of the line $y=\dfrac{1}{2}$ is:
Student are required to note that in $y=\dfrac{1}{2}$ , we have a coefficient of y is 1, so the coefficient of x is equal to the slope of the given line. Also, when we have the general equation of the line as ax + by + c = 0, we can plot them by just getting two or three coordinate or point lying on the line and then we will plot those point on the graph and after joining those point we will get the required line.