Question

How do you graph $y = x + 4$ ?

Answer 1

Hint: Whenever they ask us to draw a graph for a straight line equation we need to have a minimum of two points, it may be intercept points or any other point. We can get the points by substituting or assuming different values for $x$ and finding the corresponding values of $y$. By using these points we can plot the graph for the given equation.

Complete step by step answer:
The given equation $y = x + 4$ is a straight line equation, where we need to have a minimum of two points to plot a graph. The two points may be intercepts that are x-intercept and y-intercept which means x-intercept is a point that passes the x-axis at $y = 0$ and the y-intercept is a point that passes the y-axis at $x = 0$. We can also find the point by taking different values for $x$ and finding the corresponding values of $y$ by substituting them back in the equation.
Now, we find the y-intercept by putting $x = 0$ in the equation $y = x + 4$
Therefore we get, $y = 1 \times 0 + 4$
$ \Rightarrow y = 4$ at $x = 0$
Now, we find the x-intercept by putting $y = 0$ in the equation $y = x + 4$
Therefore we get, $0 = x + 4$
$ \Rightarrow x = - 4$ at $y = 0$
For better understanding, we take some more points for $x$ and find the corresponding values of $y$.
Let us substitute $x = 1$ in the equation $y = x + 4$, we get
$y = 1 \times 1 + 4$
$ \Rightarrow y = 1 + 4 = 5$
Now, substitute $x = 2$ in the equation $y = x + 4$, we get
$y = 1 \times 2 + 4$
$ \Rightarrow y = 2 + 4 = 6$
So now we have points which are enough to draw a graph.
Plot the graph for the points, $(0,4)$, $\left( { - 4,0} \right)$ , $(1,5)$ and $(2,6)$ .
The graph for the above points is as shown below:

Note:
Whenever they ask us to draw a graph by giving an equation, then just assume values for one unknown that is $x$ and find the corresponding values of another unknown that is $y$. Plot the same on a graph sheet. We require a minimum of two points to draw a graph but for your understanding try to take some more points and draw the graph as per the points.