Question

How do you graph $ y = \sqrt {x - 2} + 3 $ ?

Answer 1

Hint: A graph of a function f is the set of ordered pairs; the equation of graph is generally represented as $ y = f\left( x \right) $ , where x and f(x) are real numbers. We substitute the value of x and we determine the value of y and then we mark the points in the graph and we join the points.

Complete step by step solution:
Here in this question, we have to plot the graph for the given function. A graph of a function is a set of ordered pairs and it is represented as $ y = f\left( x \right) $ , where x and f(x) are real numbers. These pairs are in the form of cartesian form and the graph is the two-dimensional graph.
First, we have to find the value of y by using the graph equation $ y = \sqrt {x - 2} + 3 $ . Let we substitute the value of x as $ 2 $ , $ 3 $ , and $ 6 $ .
Now we consider the value of x as $ 2 $ , the value of y is
 $ \Rightarrow y = \sqrt {2 - 2} + 3 $
 $ \Rightarrow y = 3 $
Now we consider the value of x as $ 3 $ , the value of y is
 $ \Rightarrow y = \sqrt {3 - 2} + 3 $
 $ \Rightarrow y = 4 $
Now we consider the value of x as $ 6 $ , the value of y is
 $ \Rightarrow y = \sqrt {6 - 2} + 3 $
 $ \Rightarrow y = 5 $
Now we draw a table for these values we have

x	$ 2 $	$ 3 $	$ 6 $
y	$ 3 $	$ 4 $	$ 5 $

The graph plotted for these point is represented below:

Note: The graph plotted is of two dimensional. The graph is plotted in x-axis versus y axis. By the equation of a graph, we can plot the graph by assuming the value of x. We can’t assume the value of y because the value of y depends on the value of x. Also do not take x=1 as it will give y value as imaginary.