How do you graph \[y = 4\]?
Answer
581.7k+ views
Hint: In the given question, it is asked to graph the line \[y = 4\]. Now, this line is going to be parallel to the x-axis because its x-coordinate is going to be zero. The given value of the y-coordinate gives us the offset from the origin horizontally, i.e., how far is the line from the origin when you count in the direction of the ordinate.
Complete step-by-step answer:
The given equation of the line is \[y = 4\]. This line is going to be parallel to the x-axis, which means that it is never going to touch the x-axis, i.e., the abscissa of this line is always going to be zero.
Now, we graph the line by taking three points right (because the value of \[y\] is positive) of the origin in the direction of the y-axis.
Additional Information:
The graph of a linear equation \[Ax + By = C\] is a line.
1. Every point on the line is a solution of the equation.
2. Every solution of this equation is a point on this line.
Note:In this question, we only need to be careful about one thing: when is the line going to be parallel to the x-axis and when it will be to y-axis. After that we just count the number of points to be fit in that orientation, then plot it on the graph and we are going to get the answer.
Complete step-by-step answer:
The given equation of the line is \[y = 4\]. This line is going to be parallel to the x-axis, which means that it is never going to touch the x-axis, i.e., the abscissa of this line is always going to be zero.
Now, we graph the line by taking three points right (because the value of \[y\] is positive) of the origin in the direction of the y-axis.
Additional Information:
The graph of a linear equation \[Ax + By = C\] is a line.
1. Every point on the line is a solution of the equation.
2. Every solution of this equation is a point on this line.
Note:In this question, we only need to be careful about one thing: when is the line going to be parallel to the x-axis and when it will be to y-axis. After that we just count the number of points to be fit in that orientation, then plot it on the graph and we are going to get the answer.
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