
How do you graph $x - 4 = 0$?
Answer
538.5k+ views
Hint: Here we are given to plot the graph for the function which is given as $x - 4 = 0$ and therefore let us make this given function as a function where we only variable on one side and constant on other and we will get $x = 4$ and know that it represents the vertical line parallel to $y - {\text{axis}}$ and passing the point $\left( {4,0} \right)$.
Complete step by step solution:
Here we are given the function $x - 4 = 0$ which is only in one variable and therefore we can convert it into the form where we have a variable on one side and the constants on the other side. So we can take $ - 4$ from LHS to RHS and we will get:
$
x - 4 = 0 \\
x = 0 + 4 \\
x = 4 \\
$
Hence we need to actually plot the graph of $x = 4$
Whenever we have the graph of $x = a$ we just need to draw the vertical line which is passing through the point $a$ on the $x - {\text{axis}}$ and is parallel to $y - {\text{axis}}$.
Hence we will get its graph as a vertical line which is passing through the point $4$ on the $x - {\text{axis}}$ and is parallel to $y - {\text{axis}}$.
Hence here we can see that we have plotted the graph of the line which is given to us as
$x - 4 = 0$
So we can also notice that every point on the plotted line has its abscissa at $4$.
Note:
Similarly when we are given to plot the graph of the line $y = a$ then we need to plot the line which is passing through $\left( {0,a} \right)$ and parallel to $x - {\text{axis}}$ and therefore we must know the procedure to plot such graphs.
Complete step by step solution:
Here we are given the function $x - 4 = 0$ which is only in one variable and therefore we can convert it into the form where we have a variable on one side and the constants on the other side. So we can take $ - 4$ from LHS to RHS and we will get:
$
x - 4 = 0 \\
x = 0 + 4 \\
x = 4 \\
$
Hence we need to actually plot the graph of $x = 4$
Whenever we have the graph of $x = a$ we just need to draw the vertical line which is passing through the point $a$ on the $x - {\text{axis}}$ and is parallel to $y - {\text{axis}}$.
Hence we will get its graph as a vertical line which is passing through the point $4$ on the $x - {\text{axis}}$ and is parallel to $y - {\text{axis}}$.
Hence here we can see that we have plotted the graph of the line which is given to us as
$x - 4 = 0$
So we can also notice that every point on the plotted line has its abscissa at $4$.
Note:
Similarly when we are given to plot the graph of the line $y = a$ then we need to plot the line which is passing through $\left( {0,a} \right)$ and parallel to $x - {\text{axis}}$ and therefore we must know the procedure to plot such graphs.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

The camels hump is made of which tissues a Skeletal class 11 biology CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Define cubit handspan armlength and footspan class 11 physics CBSE

How do I convert ms to kmh Give an example class 11 physics CBSE

The percentage of free SO3 in oleum sample which is class 11 chemistry CBSE

