
How do you graph the line \[y = - 3x + 3\]?
Answer
542.4k+ views
Hint: Here, we are given a linear equation in two variables. We will substitute different values of \[x\] in the given equation to find corresponding values of \[y\]. This will give us the coordinate points and using these points we will draw the graph of the given equation.
Complete Step by Step Solution:
We are given an equation of a line-
\[y = - 3x + 3\]……………………………………………………………………………………………..\[\left( 1 \right)\]
Now, we will find the coordinates for the given equation of a line.
Now, by substituting \[x = 0\] in equation\[\left( 1 \right)\] , we get
\[y = - 3\left( 0 \right) + 3\]
\[ \Rightarrow y = 3\]
Substituting \[x = 1\] in equation \[\left( 1 \right)\] , we get
\[y = - 3\left( 1 \right) + 3\]
\[ \Rightarrow y = 0\]
The co-ordinates \[\left( {0,3} \right)\] and \[\left( {1,0} \right)\] are the \[x\]-intercept and \[y\] -intercept respectively.
Now, by substituting \[x = 2\] in equation \[\left( 1 \right)\] , we get
\[y = - 3\left( 2 \right) + 3\]
\[ \Rightarrow y = - 3\]
Substituting \[x = 3\] in equation \[\left( 1 \right)\], we get
\[y = - 3\left( 3 \right) + 3\]
\[ \Rightarrow y = - 6\]
Now, by substituting \[x = 4\] in equation \[\left( 1 \right)\], we get
\[y = - 3\left( 4 \right) + 3\]
\[ \Rightarrow y = - 9\]
So, the coordinates of the equation of line are \[\left( {0,3} \right)\],\[\left( {1,0} \right)\] ,\[\left( {2, - 3} \right)\] ,\[\left( {3, - 6} \right)\] and \[\left( {4, - 9} \right)\]
Therefore, the coordinates of the equation of line are \[\left( {0,3} \right)\],\[\left( {1,0} \right)\] ,\[\left( {2, - 3} \right)\] ,\[\left( {3, - 6} \right)\] and \[\left( {4, - 9} \right)\].
Now, we plot the graph for the co-ordinates, we get
Note:
We will solve the linear equation in two variables by the method of substitution to find the solution set at different points. Thus the solution set becomes the coordinates of the point in the graph for the linear equation. Linear equation in two variables is an equation with the highest power of 1 in two variables. Thus the graph of a linear equation is always a straight line. The given equation of the line is in the slope-intercept form\[y = mx + c\] where \[m\] is the slope and \[c\] is the \[y\]-intercept. A point crossing the x-axis is called x-intercept and A point crossing the y-axis is called the y-intercept.
Complete Step by Step Solution:
We are given an equation of a line-
\[y = - 3x + 3\]……………………………………………………………………………………………..\[\left( 1 \right)\]
Now, we will find the coordinates for the given equation of a line.
Now, by substituting \[x = 0\] in equation\[\left( 1 \right)\] , we get
\[y = - 3\left( 0 \right) + 3\]
\[ \Rightarrow y = 3\]
Substituting \[x = 1\] in equation \[\left( 1 \right)\] , we get
\[y = - 3\left( 1 \right) + 3\]
\[ \Rightarrow y = 0\]
The co-ordinates \[\left( {0,3} \right)\] and \[\left( {1,0} \right)\] are the \[x\]-intercept and \[y\] -intercept respectively.
Now, by substituting \[x = 2\] in equation \[\left( 1 \right)\] , we get
\[y = - 3\left( 2 \right) + 3\]
\[ \Rightarrow y = - 3\]
Substituting \[x = 3\] in equation \[\left( 1 \right)\], we get
\[y = - 3\left( 3 \right) + 3\]
\[ \Rightarrow y = - 6\]
Now, by substituting \[x = 4\] in equation \[\left( 1 \right)\], we get
\[y = - 3\left( 4 \right) + 3\]
\[ \Rightarrow y = - 9\]
So, the coordinates of the equation of line are \[\left( {0,3} \right)\],\[\left( {1,0} \right)\] ,\[\left( {2, - 3} \right)\] ,\[\left( {3, - 6} \right)\] and \[\left( {4, - 9} \right)\]
Therefore, the coordinates of the equation of line are \[\left( {0,3} \right)\],\[\left( {1,0} \right)\] ,\[\left( {2, - 3} \right)\] ,\[\left( {3, - 6} \right)\] and \[\left( {4, - 9} \right)\].
Now, we plot the graph for the co-ordinates, we get
Note:
We will solve the linear equation in two variables by the method of substitution to find the solution set at different points. Thus the solution set becomes the coordinates of the point in the graph for the linear equation. Linear equation in two variables is an equation with the highest power of 1 in two variables. Thus the graph of a linear equation is always a straight line. The given equation of the line is in the slope-intercept form\[y = mx + c\] where \[m\] is the slope and \[c\] is the \[y\]-intercept. A point crossing the x-axis is called x-intercept and A point crossing the y-axis is called the y-intercept.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

