
How do you graph \[f(x) = {x^2} - 4x + 5\] ?
Answer
533.7k+ views
Hint: In order graph the parabola to the above quadratic equation, first identify the nature of roots of the equation by finding the value of the determinant using the formula $D = {b^2} - 4ac,D > 0$ means the both the roots are distinct and real.
The given expression is a quadratic polynomial. The graph of the quadratic polynomial is a parabola, with the horns pointing upwards if \[a > 0\].
Complete step-by-step solution:
\[{x^2} - 4x + 5\] Is similar to \[a{x^2} + bx + c\]
It can be observed that \[a > 0\]
Therefore, it will be an upward opening parabola. Now we need to find the intercepts of the parabola.
For $y$-intercept, substituting \[x = 0\]
\[f(x) = {x^2} - 4x + 5\]
After substitution,
\[ \Rightarrow f(0) = {(0)^2} - 4(0) + 5\]
Now Simplified,
\[ \Rightarrow f(0) = 5\]
For x-intercept, substituting \[y = 0\]
\[ \Rightarrow {x^2} - 4x + 5 = 0\]
Roots of the above equation can be found by using the discriminant using the following formula
\[{x_{1,2}} = \dfrac{{\left( { - b \pm \sqrt {{b^2} - 4ac} } \right)}}{{2a}}\]
Substitute the values of the given
\[ \Rightarrow {x_{1,2}} = \dfrac{{\left( { - ( - 4) \pm \sqrt {{{( - 4)}^2} - 4(1)(5)} } \right)}}{{2(1)}}\]
On simplified,
\[ \Rightarrow {x_{1,2}} = \dfrac{{\left( {4 \pm \sqrt {16 - 20} } \right)}}{2}\]
By calculating,
${x_{1,2}} = \left( {\dfrac{{4 \pm 2i}}{2}} \right)$
\[ \Rightarrow \Delta < 0\]Therefore, no intercepts.
Now, to find the vertex, we follow the following steps-
$X - vertex{\text{ will be }}$
\[{x_v} = - \dfrac{b}{{2a}}\]
\[ \Rightarrow {x_v} = - \dfrac{{ - 4}}{2}\]
$\therefore {x_v} = 2$
$Y - vertex{\text{ will be}}$
\[{y_v} = - \dfrac{\Delta }{{4a}}\]
\[ \Rightarrow {y_v} = - \dfrac{{ - 4}}{4} = 1\]
Note: A quadratic equation
\[a{x^2} + bx + c\],
with the leading coefficient \[a \ne 0\], has two roots that may be real - equal or different - or complex. The roots can be found from the quadratic formula:
\[{x_{1,2}} = \dfrac{{\left( { - b \pm \sqrt {{b^2} - 4ac} } \right)}}{{2a}}\],
In addition to the four arithmetic operations, the formula includes a square root. The expression under the square root, \[D = {b^2} - 4ac\] - known as the discriminant - may be positive, zero, or negative. Correspondingly, the equation may have two real and distinct roots, two equal real roots, or two conjugate complex roots.
The applet allows one to experiment by changing the coefficients of the polynomial by dragging the three scrollbars at the top of the applet.)
(The maximum and minimum values on the axes can also be changed by clicking at the numbers at the endpoints - a little off their vertical mid-axis.)
The graph of the quadratic polynomial is a parabola, with the horns pointing upwards if \[a > 0\] or downwards if \[a < 0\].
Observe on the graph the behavior of the roots as you change the other two coefficients, b and c. If real, they lie on the x-axis symmetrically with respect to the vertical line through the parabola's extreme point. If complex, they simply lie on that line symmetrically with respect to the x-axis.
The given expression is a quadratic polynomial. The graph of the quadratic polynomial is a parabola, with the horns pointing upwards if \[a > 0\].
Complete step-by-step solution:
\[{x^2} - 4x + 5\] Is similar to \[a{x^2} + bx + c\]
It can be observed that \[a > 0\]
Therefore, it will be an upward opening parabola. Now we need to find the intercepts of the parabola.
For $y$-intercept, substituting \[x = 0\]
\[f(x) = {x^2} - 4x + 5\]
After substitution,
\[ \Rightarrow f(0) = {(0)^2} - 4(0) + 5\]
Now Simplified,
\[ \Rightarrow f(0) = 5\]
For x-intercept, substituting \[y = 0\]
\[ \Rightarrow {x^2} - 4x + 5 = 0\]
Roots of the above equation can be found by using the discriminant using the following formula
\[{x_{1,2}} = \dfrac{{\left( { - b \pm \sqrt {{b^2} - 4ac} } \right)}}{{2a}}\]
Substitute the values of the given
\[ \Rightarrow {x_{1,2}} = \dfrac{{\left( { - ( - 4) \pm \sqrt {{{( - 4)}^2} - 4(1)(5)} } \right)}}{{2(1)}}\]
On simplified,
\[ \Rightarrow {x_{1,2}} = \dfrac{{\left( {4 \pm \sqrt {16 - 20} } \right)}}{2}\]
By calculating,
${x_{1,2}} = \left( {\dfrac{{4 \pm 2i}}{2}} \right)$
\[ \Rightarrow \Delta < 0\]Therefore, no intercepts.
Now, to find the vertex, we follow the following steps-
$X - vertex{\text{ will be }}$
\[{x_v} = - \dfrac{b}{{2a}}\]
\[ \Rightarrow {x_v} = - \dfrac{{ - 4}}{2}\]
$\therefore {x_v} = 2$
$Y - vertex{\text{ will be}}$
\[{y_v} = - \dfrac{\Delta }{{4a}}\]
\[ \Rightarrow {y_v} = - \dfrac{{ - 4}}{4} = 1\]
Note: A quadratic equation
\[a{x^2} + bx + c\],
with the leading coefficient \[a \ne 0\], has two roots that may be real - equal or different - or complex. The roots can be found from the quadratic formula:
\[{x_{1,2}} = \dfrac{{\left( { - b \pm \sqrt {{b^2} - 4ac} } \right)}}{{2a}}\],
In addition to the four arithmetic operations, the formula includes a square root. The expression under the square root, \[D = {b^2} - 4ac\] - known as the discriminant - may be positive, zero, or negative. Correspondingly, the equation may have two real and distinct roots, two equal real roots, or two conjugate complex roots.
The applet allows one to experiment by changing the coefficients of the polynomial by dragging the three scrollbars at the top of the applet.)
(The maximum and minimum values on the axes can also be changed by clicking at the numbers at the endpoints - a little off their vertical mid-axis.)
The graph of the quadratic polynomial is a parabola, with the horns pointing upwards if \[a > 0\] or downwards if \[a < 0\].
Observe on the graph the behavior of the roots as you change the other two coefficients, b and c. If real, they lie on the x-axis symmetrically with respect to the vertical line through the parabola's extreme point. If complex, they simply lie on that line symmetrically with respect to the x-axis.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

