
How do you graph $4x - 3y = 6$ ?
Answer
528k+ views
Hint: We will first start by evaluating the y-intercept mathematically. We take all the like terms to one side and all the alike terms to the other side. Then we start plotting the graph, first we will mark all the points and then finally plot the graph.
Complete step-by-step solution:
We start with the given equation $4x - 3y = 6$.
Now here we will add $3y$ to both sides.
$4x - 3y = 6$
$4x - 3y + 3y = 6 + 3y$
Now we rearrange the terms.
$4x = 6 + 3y$
Now we will divide both the sides by $3$ in order to get the value of $y$.
Hence, the equation will become.
\[4x = 6 + 3y\]
\[\dfrac{{4x}}{3} = \dfrac{{6 + 3y}}{3}\]
Now here, we break the fraction.
\[\dfrac{{4x}}{3} = \dfrac{6}{3} + \dfrac{{3y}}{3}\]
Now reduce the terms in the equation.
\[\dfrac{{4x}}{3} = 2 + y\]
Now rearrange the terms in order to get this equation into slope point form that is $y = mx + c$.
So, the equation will become, \[y = \dfrac{{4x}}{3} - 2\].
Now if we compare values with our given equation and the slope point form, then we get the values as $m = \dfrac{4}{3}$ and $ \Rightarrow c = - 2$
We know that $c$ is the y-intercept. Y-intercept is the point where the graph intersects with the y-axis.so, now we have got one point $(0, - 2)$.
Now for the other point we substitute $y = 0$.
\[y = \dfrac{{4x}}{3} - 2\]
\[0 = \dfrac{{4x}}{3} - 2\]
\[\dfrac{{4x}}{3} = 2\]
\[4x = 6\]
\[x = \dfrac{6}{4}\]
\[ \Rightarrow x = \dfrac{3}{2}\]
That is,
\[ \Rightarrow x = 1.5\]
So, the other point is $\left( {1.5,0} \right)$
Therefore, now we have the points, $\left( {1.5,0} \right)$ and $(0, - 2)$.
So, now we will plot the graph.
Scale:
X-axis = 1 unit = 0.5 unit
Y-axis = 1 unit = 0.5 unit
All we did was join the intercept by a straight line and we extended it.
Note: While evaluating the y-intercept, make sure to take all the y-terms to one side and all the other terms to another side. While making a table for the values of $x$ and $y$ make sure you back trace the values to avoid any mistakes. While plotting graphs, always start with the drawing of axes then the points and then join all the points.
Complete step-by-step solution:
We start with the given equation $4x - 3y = 6$.
Now here we will add $3y$ to both sides.
$4x - 3y = 6$
$4x - 3y + 3y = 6 + 3y$
Now we rearrange the terms.
$4x = 6 + 3y$
Now we will divide both the sides by $3$ in order to get the value of $y$.
Hence, the equation will become.
\[4x = 6 + 3y\]
\[\dfrac{{4x}}{3} = \dfrac{{6 + 3y}}{3}\]
Now here, we break the fraction.
\[\dfrac{{4x}}{3} = \dfrac{6}{3} + \dfrac{{3y}}{3}\]
Now reduce the terms in the equation.
\[\dfrac{{4x}}{3} = 2 + y\]
Now rearrange the terms in order to get this equation into slope point form that is $y = mx + c$.
So, the equation will become, \[y = \dfrac{{4x}}{3} - 2\].
Now if we compare values with our given equation and the slope point form, then we get the values as $m = \dfrac{4}{3}$ and $ \Rightarrow c = - 2$
We know that $c$ is the y-intercept. Y-intercept is the point where the graph intersects with the y-axis.so, now we have got one point $(0, - 2)$.
Now for the other point we substitute $y = 0$.
\[y = \dfrac{{4x}}{3} - 2\]
\[0 = \dfrac{{4x}}{3} - 2\]
\[\dfrac{{4x}}{3} = 2\]
\[4x = 6\]
\[x = \dfrac{6}{4}\]
\[ \Rightarrow x = \dfrac{3}{2}\]
That is,
\[ \Rightarrow x = 1.5\]
So, the other point is $\left( {1.5,0} \right)$
Therefore, now we have the points, $\left( {1.5,0} \right)$ and $(0, - 2)$.
So, now we will plot the graph.
Scale:
X-axis = 1 unit = 0.5 unit
Y-axis = 1 unit = 0.5 unit
All we did was join the intercept by a straight line and we extended it.
Note: While evaluating the y-intercept, make sure to take all the y-terms to one side and all the other terms to another side. While making a table for the values of $x$ and $y$ make sure you back trace the values to avoid any mistakes. While plotting graphs, always start with the drawing of axes then the points and then join all the points.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

