How do you find the value of $\sec (315)?$
Answer
559.2k+ views
Hint: In the question, it is not given that the argument of the secant function is either in degrees or in radians, so better solve by taking both the units. In degree unit case, subtract the given argument with ${360^0}$ and in radians case, divide the argument with $2\pi $ and take the remainder as the new argument and then find the value.
Complete step by step answer:
In order to find the value of $\sec (315)$, we will divide it into two cases on the basis of its unit, i.e. degrees and radians (since unit of angle is not mentioned in the question, so we will take both of them).
Case I: Taking degree as the unit of the angle,
In this case, since degree is the unit so we can also write it as $\sec \left( {{{315}^0}} \right)$
Now to find the value, since the angle is lying in the fourth quadrant so we will subtract it from ${360^0}$ and take the result as the new argument,
$
\sec \left( {{{315}^0}} \right) = \sec \left( {{{360}^0} - {{315}^0}} \right) \\
= \sec \left( {{{45}^0}} \right) \\
= \sqrt 2 \\
$
Case II: Taking radians as the unit of angle,
Here to find the principal argument of the given argument we will divide the given angle with $2\pi $ and take the remainder as the new argument,
$315 \div 2\pi = 50\pi ,\;{\text{and}}\;0.84$ as the remainder,
Now, we will take $0.84$ as the new argument,
We will get $\sec (0.84)$
But we cannot calculate this value without a calculator, but we can find an approximate value,
Since $0.84$ lies somewhere between $\dfrac{\pi }{6}\;{\text{and}}\;\dfrac{\pi }{3}$ so we can take its approximate value as $1.49$
Note: In both the cases we have calculated the value of secant according to the quadrant in which the argument is lying, so that we have given it a positive or negative sign according to its argument. So you should also take care of the quadrant.
Complete step by step answer:
In order to find the value of $\sec (315)$, we will divide it into two cases on the basis of its unit, i.e. degrees and radians (since unit of angle is not mentioned in the question, so we will take both of them).
Case I: Taking degree as the unit of the angle,
In this case, since degree is the unit so we can also write it as $\sec \left( {{{315}^0}} \right)$
Now to find the value, since the angle is lying in the fourth quadrant so we will subtract it from ${360^0}$ and take the result as the new argument,
$
\sec \left( {{{315}^0}} \right) = \sec \left( {{{360}^0} - {{315}^0}} \right) \\
= \sec \left( {{{45}^0}} \right) \\
= \sqrt 2 \\
$
Case II: Taking radians as the unit of angle,
Here to find the principal argument of the given argument we will divide the given angle with $2\pi $ and take the remainder as the new argument,
$315 \div 2\pi = 50\pi ,\;{\text{and}}\;0.84$ as the remainder,
Now, we will take $0.84$ as the new argument,
We will get $\sec (0.84)$
But we cannot calculate this value without a calculator, but we can find an approximate value,
Since $0.84$ lies somewhere between $\dfrac{\pi }{6}\;{\text{and}}\;\dfrac{\pi }{3}$ so we can take its approximate value as $1.49$
Note: In both the cases we have calculated the value of secant according to the quadrant in which the argument is lying, so that we have given it a positive or negative sign according to its argument. So you should also take care of the quadrant.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

