How do you find the value of \[\cot 0\]?
Answer
585.3k+ views
Hint: Real functions which relate any angle of a right angled triangle to the ratio of any two of its sides are Trigonometric functions. We can also use geometric definitions to evaluate trigonometric values. Here, it’s important that we know the sine of theta is the ratio of the opposite side to the hypotenuse and the cosine of theta is the ratio of the adjacent side (base) to the hypotenuse. Also, it is known that the ratio of cosine of theta to the sine of theta is cot of theta.
Complete step-by-step answer:
According to the given data, we need to evaluate \[\cot 0\]
If in a right angled triangle \[\theta \] represents one of its acute angle then by definition we can write
\[\sin \theta = \dfrac{{Opposite}}{{Hypotenuse}}\]
Also,\[\cos \theta = \dfrac{{Base}}{{Hypotenuse}}\]
Thereafter we know that,
\[\cot \theta = \dfrac{1}{{\tan \theta }} = \dfrac{{\cos \theta }}{{\sin \theta }} = \dfrac{{Base}}{{Opposite}}\]
Therefore,
\[\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}\]
\[ \Rightarrow \cot \theta = \dfrac{{\cos 0}}{{\sin 0}}\].
Hence, it is known to us that \[\cos 0 = 1\] and \[\sin 0 = 0\].
When we substitute the values in the expression we get,
\[ \Rightarrow \cot \theta = \dfrac{1}{0} = \infty \]
This gives rise to the fact that \[\cot x\] doesn't exist for \[x = n\pi \].
Hence, the value of \[\cot 0\] is not defined (Infinity).
Note: One should be careful while evaluating trigonometric values and rearranging the terms to convert from one function to the other. Trigonometric functions are real functions which relate any angle of a right angled triangle to the ratio of any two of its sides. The widely used ones are sin, cos and tan. While the rest can be referred to as the reciprocal of the others, i.e., cosec, sec and cot respectively. If in a right angled triangle θ represents one of its acute angles then, \[\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}\].
Complete step-by-step answer:
According to the given data, we need to evaluate \[\cot 0\]
If in a right angled triangle \[\theta \] represents one of its acute angle then by definition we can write
\[\sin \theta = \dfrac{{Opposite}}{{Hypotenuse}}\]
Also,\[\cos \theta = \dfrac{{Base}}{{Hypotenuse}}\]
Thereafter we know that,
\[\cot \theta = \dfrac{1}{{\tan \theta }} = \dfrac{{\cos \theta }}{{\sin \theta }} = \dfrac{{Base}}{{Opposite}}\]
Therefore,
\[\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}\]
\[ \Rightarrow \cot \theta = \dfrac{{\cos 0}}{{\sin 0}}\].
Hence, it is known to us that \[\cos 0 = 1\] and \[\sin 0 = 0\].
When we substitute the values in the expression we get,
\[ \Rightarrow \cot \theta = \dfrac{1}{0} = \infty \]
This gives rise to the fact that \[\cot x\] doesn't exist for \[x = n\pi \].
Hence, the value of \[\cot 0\] is not defined (Infinity).
Note: One should be careful while evaluating trigonometric values and rearranging the terms to convert from one function to the other. Trigonometric functions are real functions which relate any angle of a right angled triangle to the ratio of any two of its sides. The widely used ones are sin, cos and tan. While the rest can be referred to as the reciprocal of the others, i.e., cosec, sec and cot respectively. If in a right angled triangle θ represents one of its acute angles then, \[\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}\].
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

