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How do you find the integral of ex2 ?

Answer
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Hint: In the above question we have to find the integral of ex2 . As you know that the integration of an exponential function is the same. Moreover, in integration, we cannot integrate any constant number. So in the final answer, we add a constant. So let us see how we can solve this problem.

Step by step solution:
Let us find the integral of ex2 . This question cannot be solved or we can say that it has no finite solution. We will use an infinite series to solve this problem.
 ex=1+x+x22!+x33!...=1+x+x22+x33+... (for all x), it follows that,
 ex2=1+x2+x42+x66+... (for all x)
We will use the formula of xn=xn+1n+1 and we will integrate each of them.
 1=x,x2=x2+12+1,x42=x4+12(4+1),x66=x6+16(6+1)
Applying integration on both the sides
 ex2=(1+x2+x42+x66+...)dx
 =C+x+x33+x510+x742+...
We can see that we don’t get any feasible finite solution for the given problem.

Note:
In the above solution we solved the integration for ex2 but we get an infinite solution. According to Wolfram Alpha theorem, the antiderivative whose graph goes through the origin as π2erfi(x) , where erfi(x) is called the "imaginary error function". Also, we have given the constant term in the integration as C.