
How do you find $\sqrt {1521} $?
Answer
530.1k+ views
Hint: To solve this we need to know the square of the number $3$ and what are all the squares of the number from $1$ to $10$ that ends with $1$. With this we are able to find the answer for this question for the given number.
Complete step by step solution:
This method which I am going to tell in this, is a trick to find the square root of any number. To do this trick, one has to know the square of the number from $1$ to $10$. Let’s move on to the problem.
Consider the question,
$\sqrt {1521} $
First, we need to look at the unit digit of the number and here the unit digit is $1$. And now pick the square number between $1$ and $10$ which ends with one, which is $1$ and $9$. Square of $1$ will be $1$ and square of 9 will be 81. Now write the number as,
$
\_1 \\
\_9 \\
$
Here our answer either should end with $1$ or $9$, there is only two possibilities and to find this we have to consider the given question which is,
$\sqrt {1521} $
Now cancel the last two digits of a number and consider the other number which is $15$, now pick the square of the number from $1$ to $10$ so that the number should be nearly lesser than $15$. And the number will be $3$, if we square $3$ we will get $9$, which is nearly lesser than $15$. Now we can write,
$
31 \\
39 \\
$
The answer for our question should be any one of these two number and to confirm this, we try to find the square of $35$, which is $1225$ and now the given question $\sqrt {1521} $ is greater than $1225$ and our required answer is $39$.
Note: While finding the root of any number, if we check the units digit, or sometimes the last two digits together, a lot of trial and error process gets cut down, as we will be able to identify with the divisibility rule which short lists some numbers to be trailed.
Complete step by step solution:
This method which I am going to tell in this, is a trick to find the square root of any number. To do this trick, one has to know the square of the number from $1$ to $10$. Let’s move on to the problem.
Consider the question,
$\sqrt {1521} $
First, we need to look at the unit digit of the number and here the unit digit is $1$. And now pick the square number between $1$ and $10$ which ends with one, which is $1$ and $9$. Square of $1$ will be $1$ and square of 9 will be 81. Now write the number as,
$
\_1 \\
\_9 \\
$
Here our answer either should end with $1$ or $9$, there is only two possibilities and to find this we have to consider the given question which is,
$\sqrt {1521} $
Now cancel the last two digits of a number and consider the other number which is $15$, now pick the square of the number from $1$ to $10$ so that the number should be nearly lesser than $15$. And the number will be $3$, if we square $3$ we will get $9$, which is nearly lesser than $15$. Now we can write,
$
31 \\
39 \\
$
The answer for our question should be any one of these two number and to confirm this, we try to find the square of $35$, which is $1225$ and now the given question $\sqrt {1521} $ is greater than $1225$ and our required answer is $39$.
Note: While finding the root of any number, if we check the units digit, or sometimes the last two digits together, a lot of trial and error process gets cut down, as we will be able to identify with the divisibility rule which short lists some numbers to be trailed.
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