
How do you factor ${{\left( x+a \right)}^{2}}-{{b}^{2}}=0$ ?
Answer
548.1k+ views
Hint: In this question, we have to find the factors of an algebraic expression. So, we will use the algebraic identity and the basic mathematical rules to get the required solution. We will first compare the given algebraic expression with the algebraic identity ${{m}^{2}}-{{n}^{2}}=0$ . Then, we will find the value of m and n. In the last, we will put the value of m and n in equation $\left( m+n \right)\left( m-n \right)=0$ , to get the required result for the solution.
Complete step by step solution:
According to the question, we have to find the factors of an algebraic expression.
So, we will apply the algebraic identity and the basic mathematical rules to get the required result.
The expression given to us is ${{\left( x+a \right)}^{2}}-{{b}^{2}}=0$ ---------------- (1)
Now, we will apply the algebraic identity, that is we know
If ${{m}^{2}}-{{n}^{2}}=0$ , then --------- (2)
$\left( m+n \right)\left( m-n \right)=0$ -------- (3)
Now, on comparing equation (1) and (2), we get the value of m and n equal to $x+a$ and $b$ respectively.
Thus, on putting the value m and n in equation (3), we get
$\left( x+a+b \right)\left( x+a-b \right)=0$ which is the required solution.
Therefore, for the algebraic expression ${{\left( x+a \right)}^{2}}-{{b}^{2}}=0$ , their factors are equal to $\left( x+a+b \right)\left( x+a-b \right)$ .
Note: While solving this equation, do step-by-step calculations properly to avoid confusion and mathematical errors. One of the methods to check your answer is use the distributive property in the solution, that is open the brackets of the solution and make the mathematical calculations, which is equal to the algebraic expression given in the problem.
Complete step by step solution:
According to the question, we have to find the factors of an algebraic expression.
So, we will apply the algebraic identity and the basic mathematical rules to get the required result.
The expression given to us is ${{\left( x+a \right)}^{2}}-{{b}^{2}}=0$ ---------------- (1)
Now, we will apply the algebraic identity, that is we know
If ${{m}^{2}}-{{n}^{2}}=0$ , then --------- (2)
$\left( m+n \right)\left( m-n \right)=0$ -------- (3)
Now, on comparing equation (1) and (2), we get the value of m and n equal to $x+a$ and $b$ respectively.
Thus, on putting the value m and n in equation (3), we get
$\left( x+a+b \right)\left( x+a-b \right)=0$ which is the required solution.
Therefore, for the algebraic expression ${{\left( x+a \right)}^{2}}-{{b}^{2}}=0$ , their factors are equal to $\left( x+a+b \right)\left( x+a-b \right)$ .
Note: While solving this equation, do step-by-step calculations properly to avoid confusion and mathematical errors. One of the methods to check your answer is use the distributive property in the solution, that is open the brackets of the solution and make the mathematical calculations, which is equal to the algebraic expression given in the problem.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

