
How do you factor \[-5{{x}^{2}}-x+4\]?
Answer
548.1k+ views
Hint: This type of problem is based on the concept of factoring a polynomial. First, we have to consider the whole polynomial with degree 2. We have to split the middle term of the quadratic polynomial in such a way that we get common terms from the first and last term. Here, the middle term is -x. We can split the middle as an addition of 4x and 5x. We have to take -5x common from the first two terms and 4 common from the last two terms. We find that (x+1) is common in the two terms. On taking the common terms, we get the factors of the polynomial.
Complete step by step solution:
According to the question, we are asked to find the factors of \[-5{{x}^{2}}-x+4\].
We have been given the polynomial is \[-5{{x}^{2}}-x+4\]. -----(1)
The given polynomial is of degree 2 and variable x.
To find the factors of the polynomial, we have to consider the middle term and split the middle term in such a way that the addition of these terms will be -1 and multiplication will be \[-5\times 4\].
We know that \[-5\times 4=-20\]. Thus the addition should be -1 and multiplication of these two numbers should be -20.
We know that -5+4=-1 and \[-5\times 4=20\].
Therefore, we get
\[-5{{x}^{2}}-x+4=-5{{x}^{2}}+\left( -5+4 \right)x+4\]
Using the distributive property, that is \[a\left( b+c \right)=ab+ac\], we get
\[-5{{x}^{2}}-x+4=-5{{x}^{2}}+\left( -5 \right)x+4x+4\]
\[\Rightarrow -5{{x}^{2}}-x+4=-5{{x}^{2}}-5x+4x+4\]
We find that -5x are common in the first two terms of the simplified polynomial and 4 are common in the last two terms of the simplified polynomial.
Let us take -5x and 4 common out of the bracket respectively.
\[\Rightarrow -5{{x}^{2}}-x+4=-5x\left( x+1 \right)+4\left( x+1 \right)\]
We find that x+1 is common in both the terms of the equation. On taking (x+1) common, we get
\[-5{{x}^{2}}-x+4=\left( x+1 \right)\left( -5x+4 \right)\]
Here, we find that the polynomial is converted as a product of two linear polynomials.
These are the factors of the given polynomial.
Therefore, the factors of \[-5{{x}^{2}}-x+4\] are x+1 and 4-5x.
Note: Whenever you get this type of problem, we should always try to make the necessary changes in the polynomial to get the factors of the polynomial which will be the required answer. If the polynomial is of degree 2, then we get two factors only. We should also avoid calculation mistakes based on sign conventions.
Complete step by step solution:
According to the question, we are asked to find the factors of \[-5{{x}^{2}}-x+4\].
We have been given the polynomial is \[-5{{x}^{2}}-x+4\]. -----(1)
The given polynomial is of degree 2 and variable x.
To find the factors of the polynomial, we have to consider the middle term and split the middle term in such a way that the addition of these terms will be -1 and multiplication will be \[-5\times 4\].
We know that \[-5\times 4=-20\]. Thus the addition should be -1 and multiplication of these two numbers should be -20.
We know that -5+4=-1 and \[-5\times 4=20\].
Therefore, we get
\[-5{{x}^{2}}-x+4=-5{{x}^{2}}+\left( -5+4 \right)x+4\]
Using the distributive property, that is \[a\left( b+c \right)=ab+ac\], we get
\[-5{{x}^{2}}-x+4=-5{{x}^{2}}+\left( -5 \right)x+4x+4\]
\[\Rightarrow -5{{x}^{2}}-x+4=-5{{x}^{2}}-5x+4x+4\]
We find that -5x are common in the first two terms of the simplified polynomial and 4 are common in the last two terms of the simplified polynomial.
Let us take -5x and 4 common out of the bracket respectively.
\[\Rightarrow -5{{x}^{2}}-x+4=-5x\left( x+1 \right)+4\left( x+1 \right)\]
We find that x+1 is common in both the terms of the equation. On taking (x+1) common, we get
\[-5{{x}^{2}}-x+4=\left( x+1 \right)\left( -5x+4 \right)\]
Here, we find that the polynomial is converted as a product of two linear polynomials.
These are the factors of the given polynomial.
Therefore, the factors of \[-5{{x}^{2}}-x+4\] are x+1 and 4-5x.
Note: Whenever you get this type of problem, we should always try to make the necessary changes in the polynomial to get the factors of the polynomial which will be the required answer. If the polynomial is of degree 2, then we get two factors only. We should also avoid calculation mistakes based on sign conventions.
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