Question

How do you evaluate \[(15-5).2\]?

Answer 1

Hint: PEMDAS rule gives the order of operators in the calculation of a mathematical problem. The full form of each initial is P= Parenthesis (brackets); E= Exponents; M= Multiply; D= Divide; A= Addition; S= Subtraction. We solve inside the brackets, then do exponents, multiply and divide before going for addition and subtraction.

Complete step by step answer:
As per the given question, we need to simplify \[(15-5).2\]. Here, we have a parenthesis multiplied with 2 and there are two terms inside the parenthesis related to the subtraction operator.
Using PEMDAS rule, first we check inside the parenthesis (that is bracket). In the given expression \[(15-5).2\], we have a bracket. So, we first solve this bracket. Inside the bracket, we have \[(15-5)\] which is a subtraction of 5 from 15. This is equal to 10. Then, we can rewrite the equation \[(15-5).2\] as
\[\Rightarrow (15-5).2=10\times 2\]
Now, we step into the next thing that is, checking for exponents. The given expression doesn’t have exponent terms. So, we check for multiplication terms. Here, the modified equation has \[10\times 2\] which is the multiplication of 10 with 2. This is equal to 20. Then, we can rewrite the equation as
\[\Rightarrow 10\times 2=20\]
\[\therefore 20\] is the required simplified form of the expression \[(15-5).2\].

Note:
One must clearly understand the PEMDAS rule before getting into the
question. We can also solve this question by expanding \[(15-5).2\] into \[(15\times 2-5\times 2)\], where \[(15\times 2)\] is 30 and \[(5\times 2)\] is 10. Hence, subtraction 10 from 30 gives the same answer 20. When we perform division, then while doing division, if we get a terminating decimal number then we have to round it.