
How do you divide $\dfrac{4-3i}{5+5i}$?
Answer
563.7k+ views
Hint: To divide the given fraction which is in the form of a complex number, we have to convert the denominator of the fraction into a real number by multiplying the number by the complex conjugate of the denominator.
Complete answer:
We have the given number as:
$\Rightarrow \dfrac{4-3i}{5+5i}$
Now to get the denominator into the real form we must multiply it with the complex conjugate,
We know that for a complex number $a+bi$, the complex conjugate for that number is $a-bi$, where the terms $a$and $b$are real numbers.
Therefore, the complex conjugate of the number $5+5i$ will be $5-5i$, therefore we will multiply the numerator and denominator of the number with the term $5-5i$.
On multiplying we get:
$\Rightarrow \dfrac{4-3i}{5+5i}\times \dfrac{(5-5i)}{(5-5i)}$
On multiplying we get:
$\Rightarrow \dfrac{(4-3i)(5-5i)}{(5+5i)(5-5i)}$
Now on distributing the terms, we get:
$\Rightarrow \dfrac{4\times 5-4\times 5i-3i\times 5+3i\times 5i}{5\times 5-5\times 5i+5i\times 5-5i\times 5i}$
On multiplying the terms, we get:
$\Rightarrow \dfrac{20-35i+15{{i}^{2}}}{25-25{{i}^{2}}}$
Now we know that the value of ${{i}^{2}}=-1$, therefore on substituting in the equation, we get-
$\Rightarrow \dfrac{20-35i+15(-1)}{25-25(-1)}$
On simplifying we get:
$\Rightarrow \dfrac{20-15-35i}{25+25}$
$\Rightarrow \dfrac{5-35i}{50}$
Now on splitting the fraction, we get:
$\Rightarrow \dfrac{5}{50}-\dfrac{35i}{50}$
On simplifying, we get:
$\Rightarrow \dfrac{1}{10}-\dfrac{7}{10}i$, which is the final answer in the form of $a+bi$ where $a=\dfrac{1}{10}$ and $b=-\dfrac{7}{10}$ which are both real numbers.
Note:
it is to be remembered that whenever a complex number is multiplied with its complex conjugate, the complex part of the number is eliminated. It can be proved as:
$(a+bi)(a-bi)={{a}^{2}}-abi+abi-{{b}^{2}}{{i}^{2}}$
On simplifying we get:
$(a+bi)(a-bi)={{a}^{2}}-{{b}^{2}}{{i}^{2}}$
Now since the ${{i}^{2}}=-1$ we can write the term as:
$(a+bi)(a-bi)={{a}^{2}}+{{b}^{2}}$.
When we multiply and divide a number by a same number, the value of the fraction does not change, this is the reason we multiplied and divided the original term by the complex conjugate.
Complete answer:
We have the given number as:
$\Rightarrow \dfrac{4-3i}{5+5i}$
Now to get the denominator into the real form we must multiply it with the complex conjugate,
We know that for a complex number $a+bi$, the complex conjugate for that number is $a-bi$, where the terms $a$and $b$are real numbers.
Therefore, the complex conjugate of the number $5+5i$ will be $5-5i$, therefore we will multiply the numerator and denominator of the number with the term $5-5i$.
On multiplying we get:
$\Rightarrow \dfrac{4-3i}{5+5i}\times \dfrac{(5-5i)}{(5-5i)}$
On multiplying we get:
$\Rightarrow \dfrac{(4-3i)(5-5i)}{(5+5i)(5-5i)}$
Now on distributing the terms, we get:
$\Rightarrow \dfrac{4\times 5-4\times 5i-3i\times 5+3i\times 5i}{5\times 5-5\times 5i+5i\times 5-5i\times 5i}$
On multiplying the terms, we get:
$\Rightarrow \dfrac{20-35i+15{{i}^{2}}}{25-25{{i}^{2}}}$
Now we know that the value of ${{i}^{2}}=-1$, therefore on substituting in the equation, we get-
$\Rightarrow \dfrac{20-35i+15(-1)}{25-25(-1)}$
On simplifying we get:
$\Rightarrow \dfrac{20-15-35i}{25+25}$
$\Rightarrow \dfrac{5-35i}{50}$
Now on splitting the fraction, we get:
$\Rightarrow \dfrac{5}{50}-\dfrac{35i}{50}$
On simplifying, we get:
$\Rightarrow \dfrac{1}{10}-\dfrac{7}{10}i$, which is the final answer in the form of $a+bi$ where $a=\dfrac{1}{10}$ and $b=-\dfrac{7}{10}$ which are both real numbers.
Note:
it is to be remembered that whenever a complex number is multiplied with its complex conjugate, the complex part of the number is eliminated. It can be proved as:
$(a+bi)(a-bi)={{a}^{2}}-abi+abi-{{b}^{2}}{{i}^{2}}$
On simplifying we get:
$(a+bi)(a-bi)={{a}^{2}}-{{b}^{2}}{{i}^{2}}$
Now since the ${{i}^{2}}=-1$ we can write the term as:
$(a+bi)(a-bi)={{a}^{2}}+{{b}^{2}}$.
When we multiply and divide a number by a same number, the value of the fraction does not change, this is the reason we multiplied and divided the original term by the complex conjugate.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

