Answer
Verified
362.4k+ views
Hint: This type of question is based on the concept of rationalizing. Here, to explain the concept let us consider a cubic root \[\dfrac{a}{\sqrt[3]{b}}\]. Here, \[\sqrt[3]{b}\] is a cubic term of b. We have to multiply \[\sqrt[3]{{{b}^{2}}}\] in both the numerator and denominator to rationalise the cubic root. Using \[\sqrt[3]{{{b}^{3}}}=b\], we can simplify the cubic root \[\dfrac{a}{\sqrt[3]{b}}\]. When we get ‘b’ alone in the denominator, we have rationalised the cubic root considered. Thus, we got the final answer.
Complete step by step answer:
According to the question, we are asked to find how to rationalize a cubic root.
Let us assume \[\dfrac{a}{\sqrt[3]{b}}\] to be a cubic root.
Let us now consider \[\dfrac{a}{\sqrt[3]{b}}\].
Now, let us multiply \[\sqrt[3]{{{b}^{2}}}\] in both the numerator and denominator of \[\dfrac{a}{\sqrt[3]{b}}\].
We get,
\[\dfrac{a}{\sqrt[3]{b}}=\dfrac{a}{\sqrt[3]{b}}\times \dfrac{\sqrt[3]{{{b}^{2}}}}{\sqrt[3]{{{b}^{2}}}}\]
On grouping the numerator and denominator, we get,
\[\Rightarrow \dfrac{a}{\sqrt[3]{b}}=\dfrac{a\sqrt[3]{{{b}^{2}}}}{\sqrt[3]{b}\times \sqrt[3]{{{b}^{2}}}}\]
We know that \[\sqrt[3]{x}\times \sqrt[3]{y}=\sqrt[3]{xy}\].
On using this property of cubic root in the above obtained expression, we get,
\[\Rightarrow \dfrac{a}{\sqrt[3]{b}}=\dfrac{a\sqrt[3]{{{b}^{2}}}}{\sqrt[3]{{{b}^{3}}}}\] ---------(1)
We know that \[\sqrt[3]{{{b}^{3}}}=b\].
Using this in equation (1), we get
\[\dfrac{a}{\sqrt[3]{b}}=\dfrac{a\sqrt[3]{{{b}^{2}}}}{b}\]
Therefore, we can rationalize the cubic root by multiplying \[\sqrt[3]{{{b}^{2}}}\] on both the numerator and denominator of the assumed cubic roots.
Hence, the cubic root \[\dfrac{a}{\sqrt[3]{b}}\] has been rationalised.
Note:
We must always multiply numerator and denominator with the cube root of the square of the term in the denominator to rationalise. We can rationalize negative cubic root also by the same way. Similarly, we can rationalize \[\dfrac{2}{\sqrt[3]{7}}\]. Here a=2 and b=7. Follow the above steps to rationalise the cubic root. We should know the square of basic numbers for easy calculations. We should avoid calculation mistakes based on sign conventions, if any.
Complete step by step answer:
According to the question, we are asked to find how to rationalize a cubic root.
Let us assume \[\dfrac{a}{\sqrt[3]{b}}\] to be a cubic root.
Let us now consider \[\dfrac{a}{\sqrt[3]{b}}\].
Now, let us multiply \[\sqrt[3]{{{b}^{2}}}\] in both the numerator and denominator of \[\dfrac{a}{\sqrt[3]{b}}\].
We get,
\[\dfrac{a}{\sqrt[3]{b}}=\dfrac{a}{\sqrt[3]{b}}\times \dfrac{\sqrt[3]{{{b}^{2}}}}{\sqrt[3]{{{b}^{2}}}}\]
On grouping the numerator and denominator, we get,
\[\Rightarrow \dfrac{a}{\sqrt[3]{b}}=\dfrac{a\sqrt[3]{{{b}^{2}}}}{\sqrt[3]{b}\times \sqrt[3]{{{b}^{2}}}}\]
We know that \[\sqrt[3]{x}\times \sqrt[3]{y}=\sqrt[3]{xy}\].
On using this property of cubic root in the above obtained expression, we get,
\[\Rightarrow \dfrac{a}{\sqrt[3]{b}}=\dfrac{a\sqrt[3]{{{b}^{2}}}}{\sqrt[3]{{{b}^{3}}}}\] ---------(1)
We know that \[\sqrt[3]{{{b}^{3}}}=b\].
Using this in equation (1), we get
\[\dfrac{a}{\sqrt[3]{b}}=\dfrac{a\sqrt[3]{{{b}^{2}}}}{b}\]
Therefore, we can rationalize the cubic root by multiplying \[\sqrt[3]{{{b}^{2}}}\] on both the numerator and denominator of the assumed cubic roots.
Hence, the cubic root \[\dfrac{a}{\sqrt[3]{b}}\] has been rationalised.
Note:
We must always multiply numerator and denominator with the cube root of the square of the term in the denominator to rationalise. We can rationalize negative cubic root also by the same way. Similarly, we can rationalize \[\dfrac{2}{\sqrt[3]{7}}\]. Here a=2 and b=7. Follow the above steps to rationalise the cubic root. We should know the square of basic numbers for easy calculations. We should avoid calculation mistakes based on sign conventions, if any.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE